MathIsimple
Lesson 2-1

Advanced Exponential Functions

Definitions, growth vs. decay, compounding, doubling time and half-life with real-world models.

Learning Objectives

  • Define and recognize exponential functions y = a^x and y = b e^{kx} with parameter meanings.
  • Determine growth vs. decay from base and rate parameters; interpret asymptotic behavior.
  • Compute compound interest and continuous compounding; compare compounding frequencies.
  • Use doubling time and half-life formulas to solve real-world problems.
  • Build and validate exponential models from context; interpret units and parameters.

Growth & Decay

Identify increasing/ decreasing behavior via base a and rate k; analyze end behavior and asymptotes.

Compounding

Discrete vs. continuous compounding; effective rates; financial applications.

Half-life

Decay modeling with physical meaning; relate to exponential constants and percent decrease.

Data Fit

Convert multiplicative change to additive logs for linearization and parameter estimation.

Time Scales

Doubling time T_d and half-life T_{1/2}; connect to k through natural logarithms.

Definition & Core Properties

An exponential function grows or decays by a constant percentage per equal time step. The two most common forms are base form and natural-base form:

y=ax,  a>0, a1y = a^x,\; a>0,\ a\neq 1
y=bekx,  b>0y = b\, e^{kx},\; b>0

Key features:

  • Domain: (,)(-\infty,\infty); Range: (0,)(0,\infty); horizontal asymptote: y=0y=0.
  • If a>1a>1 or k>0k>0, the function is increasing; if 0<a<10<a<1 or k<0k<0, it is decreasing.
  • All exponential graphs pass through (0,1)(0,1) in base form; (0,b)(0,b) in natural-base form.

Growth vs. Decay & Percentage Interpretation

A convenient modeling form uses a growth factor per period:

y(t)=y0(1+r)t/Δty(t) = y_0 (1+r)^{t/\Delta t}

Here rr is the percentage change per base period Δt\Delta t. If r>0r>0, we have growth; if r<0r<0, we have decay.

Converting to natural-base form yields y(t)=y0ekty(t) = y_0 e^{kt}, wherek=ln(1+r)Δtk = \frac{\ln(1+r)}{\Delta t}. For small |r|, the approximationkrΔtk \approx \frac{r}{\Delta t} holds.

Compound Interest & Continuous Compounding

Financial growth often uses compounding. With nominal annual rate rr, principalPP, and nn compounding periods per year for tt years:

A=Pleft(1+fracrnight)ntA = Pleft(1+ frac{r}{n} ight)^{nt}

As nn\to\infty, we obtain continuous compounding with base ee:

A=PertA = Pe^{rt}

Effective Annual Rate (EAR) compares different compounding frequencies on an equal footing:

EAR=left(1+fracrnight)n1,quadEARcont=er1EAR = left(1+ frac{r}{n} ight)^{n} - 1,quad EAR_{cont} = e^{r}-1

Doubling Time and Half-Life

For y(t)=y0ekty(t) = y_0 e^{kt} with k>0k>0 (growth), the doubling timeTdT_d solves ekTd=2e^{k T_d} = 2, hence:

Td=fracln2kT_d = frac{ln 2}{k}

For decay (k<0k<0), the half-life T1/2T_{1/2} makesekT1/2=frac12e^{k T_{1/2}} = frac{1}{2}, so:

T1/2=fracln2kT_{1/2} = frac{ln 2}{|k|}

These relations allow quick reasoning about time scales in biology, physics, and finance.

Asymptotic Behavior & Transformations

Exponentials have horizontal asymptote y=0y=0. With vertical shift +c+c, the asymptote becomesy=cy=c. Horizontal scaling modifies the time scale; vertical scaling changes initial value.

  • Vertical stretch: y=Aekxy = A e^{kx} scales all values by AA.
  • Horizontal scaling: y=ek(ax)y = e^{k(ax)} changes growth rate to kaka.
  • Vertical shift: y=ekx+cy = e^{kx} + c shifts asymptote to y=cy=c.

Worked Examples

Example 1: Compare Discrete vs. Continuous Compounding

Invest P=10000P=10000 at nominal annual rate r=5%r=5\% fort=5t=5 years. Compute with annual, monthly, and continuous compounding, and compare.

Annual (n=1): A=10000(1+0.05)5A=10000(1+0.05)^{5} ≈ 12763

Monthly (n=12): A=10000left(1+frac0.0512ight)60A=10000left(1+ frac{0.05}{12} ight)^{60} ≈ 12834

Continuous: A=10000e0.05cdot5A=10000e^{0.05cdot 5} ≈ 12840

More frequent compounding yields higher returns; continuous compounding is the theoretical maximum for a given nominal rate.

Example 2: Radioactive Decay and Half-Life

A substance decays according to m(t)=m0ektm(t)=m_0 e^{kt} with half-life 30 days. Findkk and compute remaining mass after 20 days when m0=200m_0=200 g.

Half-life relation: ekcdot30=frac12e^{kcdot 30}= frac{1}{2}k=fracln(1/2)30=fracln230k= frac{ln(1/2)}{30}=- frac{ln 2}{30}

After 20 days: m(20)=200left(frac12ight)20/30m(20)=200left( frac{1}{2} ight)^{20/30} ≈ 126 g

The mass decreases by a constant percentage per equal time interval; the decay is multiplicative, not linear.

Example 3: Determine Doubling Time

A population follows P(t)=P0e0.08tP(t)=P_0 e^{0.08t} with tt in years. Find the doubling time.

Td=fracln20.08T_d= frac{ln 2}{0.08} ≈ 8.66 years.

At 8% continuous growth, the quantity doubles about every 8.66 years.

Example 4: Effective Annual Rate (EAR)

Compare EAR for r=12%r=12\% with monthly compounding vs. continuous compounding.

Monthly: EAR=(1+0.12/12)121EAR=(1+0.12/12)^{12}-1 ≈ 12.68%

Continuous: EARcont=e0.121EAR_{cont}=e^{0.12}-1 ≈ 12.75%

Continuous compounding gives a slightly higher effective rate for the same nominal rate.

Modeling Scenarios

Finance: Savings Growth

With monthly deposits and monthly compounding, the future value follows an annuity-growth model. For simplicity, if the deposit occurs at period end, the closed form is:

FV = D, rac{left(1+ frac{r}{n} ight)^{nt}-1}{ frac{r}{n}}

This complements the single-sum formulas and is vital in budgeting and retirement planning.

Science: Pharmacokinetics

Drug concentration in blood often decays exponentially after reaching peak level. If the elimination constant is kk, the half-life is T1/2=ln2/kT_{1/2}=ln 2/|k|. Repeated dosing superposes exponentials.

C(t)=C0ekt,quadk<0C(t)=C_0 e^{kt},quad k<0

Understanding half-life informs safe dosing intervals and steady-state analysis.

Earth Science: Cooling Laws

Newton's Law of Cooling often yields an exponential approach to ambient temperature. With ambient TaT_a and initial T0T_0:

T(t)=Ta+(T0Ta)ektT(t)=T_a + (T_0-T_a) e^{kt}

The asymptote shifts from 0 to TaT_a, demonstrating transformation effects on exponential functions.

Demography: Population Growth

Short-run population growth can often be approximated by an exponential with rate kk. The doubling time provides an intuitive summary of pace.

P(t)=P0ekt,quadTd=ln2/kP(t)=P_0 e^{kt},quad T_d=ln 2/k

In the long run, logistic models may be more appropriate, but exponential fits are useful locally.

Practice Problems

Problem 1: Determine Growth or Decay

Classify each function as growth or decay and state its asymptote:

  • y=5cdot(0.7)xy=5cdot (0.7)^x
  • y=2e0.3xy=2e^{0.3x}
  • y=108cdot(0.5)xy=10 - 8cdot (0.5)^x
Show Solution

(a) Decay (factor 0.7<1), asymptote y=0.

(b) Growth (k=0.3>0), asymptote y=0.

(c) Decay toward y=10 (vertical shift), asymptote y=10.

Problem 2: Continuous Compounding

Find tt such that A=2PA=2P under continuous compounding with rate rr.

Show Solution

We solve Pert=2PPe^{rt}=2Pert=2e^{rt}=2t=fracln2rt= frac{ln 2}{r}.

Problem 3: Find k from Two Data Points

A culture grows from 100 to 135 in 2 hours. Assume N(t)=N0ektN(t)=N_0e^{kt}. Find kk and the doubling time.

Show Solution

frac135100=e2k frac{135}{100}=e^{2k}k=frac12ln(1.35)k= frac{1}{2}ln(1.35) ≈ 0.1508 h−1.

Td=ln2/kT_d=ln 2/k ≈ 4.596 hours.

Problem 4: Half-Life Application

A medication has half-life 6 hours. If the initial dose produces concentration 40 units, find concentration after 18 hours.

Show Solution

Three half-lives: 40cdot(1/2)3=540cdot (1/2)^3=5 units.

Problem 5: Determine Asymptote after Transformation

For y=73e0.4xy=7-3e^{-0.4x}, state growth/decay and its horizontal asymptote.

Show Solution

Decay toward y=7y=7; asymptote is y=7y=7 as xoinftyx oinfty.

Key Takeaways

  • Exponential change is multiplicative with constant percentage per equal interval.
  • Continuous compounding uses erte^{rt} and typically yields the highest value for given nominal rate.
  • Doubling time and half-life connect directly to the exponential rate via natural logarithms.
  • Transformations shift asymptotes and scale initial values but preserve exponential character.

Log-Linearization Workshop

Turning Products into Sums

For data following y=Cekty=Ce^{kt}, take ln to get lny=lnC+ktln y = ln C + kt (linear in t).

Parameter Estimation

Estimate slope k by linear regression on (t,lny)(t,ln y); intercept gives lnCln C.

Extended Applications

Finance: Mortgage Balance Decay

  • Model remaining balance with effective rate per period.
  • Compare discrete compounding vs. continuous approximation.
  • Discuss sensitivity to rate changes and payment cadence.

Epidemiology: Early-Phase Spread

  • Use N(t)=N0ektN(t)=N_0e^{kt} with growth constant linked to R₀.
  • Fit k from case counts; interpret doubling time.
  • Explain limits of exponential once interventions begin.

Ecology: Fish Population Growth

  • Estimate short-term growth rate from tagging surveys.
  • Compute time to double under favorable conditions.
  • Note logistic saturation beyond the short time horizon.

Physics: Capacitor Charging

  • Model voltage as V(t)=V0(1ekt)V(t)=V_0(1-e^{kt}) with k<0k<0.
  • Identify time constant and 63% rise time.
  • Contrast with discharge modeled by pure exponential decay.

Chemistry: First-Order Reaction

  • Concentration C(t)=C0ektC(t)=C_0e^{kt}, estimate k via ln plot.
  • Relate half-life to k|k| and temperature effects.
  • Discuss deviations from first-order at high concentration.

Computer Science: Algorithmic Growth

  • Contrast exponential time O(2n)O(2^n) vs. polynomial.
  • Use doubling argument to estimate break-even sizes.
  • Explain why small input increases cause huge runtime jumps.

Economics: Inflation and Prices

  • Approximate CPI increases with continuous rate k.
  • Compute doubling time of prices at various k.
  • Discuss compounding effects on long-term planning.

Earth Science: Seismic Aftershock Decay

  • Short-run decay rates approximated exponentially.
  • Estimate half-life of aftershock intensity.
  • Explain transition to power-law for longer horizons.

Biology: Bacterial Culture

  • Estimate k from OD readings at equal intervals.
  • Compute generation time and compare media conditions.
  • Discuss limits due to nutrients and waste buildup.

Medicine: Tumor Volume Doubling

  • Use imaging data to estimate exponential growth.
  • Interpret doubling time with clinical caution.
  • Note transitions to Gompertz/logistic models later.

Energy: Battery Self-Discharge

  • Model loss with small negative k over months.
  • Estimate capacity after storage; compare chemistries.
  • Relate to temperature dependence of k.

Environmental: CO₂ Accumulation

  • Short-term exponential rise from emissions scenarios.
  • Compute time to reach given concentration threshold.
  • Discuss feedbacks that alter exponential trend.

Technology: User Growth

  • Fit k from weekly active users in early stage.
  • Translate to doubling time for planning capacity.
  • Warn about saturation and network effects later.

Practice Bank

Bank 1: Identify Form & Parameters

  1. Given data, decide base vs. natural-base model.
  2. Estimate kk or base aa with units.
  3. State asymptote and intercepts.

Bank 2: Compounding Comparisons

  1. Compute annual, monthly, and continuous values.
  2. Report EAR and rank options.
  3. Explain differences qualitatively.

Bank 3: Doubling/Half-Life

  1. Find TdT_d or T1/2T_{1/2}.
  2. Interpret in plain language.
  3. Check feasibility bounds.

Bank 4: Fit from Two Points

  1. Compute kk using two measurements.
  2. Predict future value at time t.
  3. Quantify percent error if data noisy.

Bank 5: Linearization

  1. Plot (t,lny)(t,ln y) and fit a line.
  2. Extract slope/intercept to get parameters.
  3. Check residuals for curvature.

Bank 6: Transformations

  1. Apply vertical shifts and stretches.
  2. Identify new asymptote and intercept.
  3. Explain effect on parameters.

Bank 7: Rate Interpretation

  1. Translate k into percent per unit time.
  2. Contrast small vs. large k scenarios.
  3. Provide a real-world analogy.

Bank 8: Mixed Compounding

  1. Convert discrete to continuous rate.
  2. Compare outcomes after fixed horizon.
  3. Decide which is preferable and why.

Bank 9: Parameter Bounds

  1. Given constraints, find allowed k range.
  2. Test extremes and interpret.
  3. State assumptions clearly.

Bank 10: Back-of-Envelope

  1. Approximate changes using ekDeltatapprox1+kDeltate^{kDelta t}approx 1+kDelta t.
  2. Check accuracy region.
  3. Compare with exact computation.

Bank 11: Piecewise Contexts

  1. Model two phases with different rates.
  2. Ensure continuity at the switch time.
  3. Interpret each phase separately.

Bank 12: Uncertainty in k

  1. Provide interval for k from data CI.
  2. Propagate to prediction interval.
  3. Discuss decision implications.

Bank 13: Unit Consistency

  1. Check units for k and time variable.
  2. Convert units and recompute.
  3. Explain changes to interpretation.

Bank 14: Parameter Solving

  1. Solve for y0y_0 and k from two conditions.
  2. State model uniquely.
  3. Validate with third checkpoint.

Bank 15: Competing Models

  1. Compare exponential vs. linear fit error.
  2. Choose model by residual analysis.
  3. Explain tradeoffs.

Bank 16: Forecasting

  1. Provide 1-, 2-, 5-period forecasts.
  2. Quantify uncertainty qualitatively.
  3. Note limits of extrapolation.

FAQ (Extended)

Q: When should I prefer ekte^{kt} over axa^x?

Use ekte^{kt} for naturally continuous change (continuous compounding, decay constants). Use axa^x for discrete-period change.

Q: How to estimate k robustly?

Prefer multi-point log–linear regression over two-point estimates; inspect residuals and outliers for model adequacy.