Master advanced derivative techniques for parametric curves and implicit relations. Learn to calculate tangent lines, interpret rates of change, and apply these concepts to real-world modeling scenarios.
Calculate dy/dx for the parametric curve!
Parametric Equations:
At t = 1
Find dy/dx for the implicit equation!
Implicit Equation:
At point (2, 3)
Parametric equations define curves using a parameter t. Instead of y = f(x), we have x = f(t) and y = g(t). This allows us to describe more complex curves, including those that aren't functions.
Given: x = 2t, y = 3t²
Step 1: Find dx/dt = 2
Step 2: Find dy/dt = 6t
Step 3: Apply chain rule: dy/dx = (dy/dt)/(dx/dt) = 6t/2 = 3t
Answer: dy/dx = 3t
Given: x = cos(t), y = sin(t) (a circle)
Step 1: dx/dt = -sin(t), dy/dt = cos(t)
Step 2: dy/dx = cos(t)/(-sin(t)) = -cot(t)
At t = π/4: dy/dx = -cot(π/4) = -1
Answer: dy/dx = -cot(t)
Given: x = t², y = t³
First derivative: dy/dx = (3t²)/(2t) = 3t/2
Second derivative: d²y/dx² = d/dx(dy/dx) = d/dt(3t/2) / (dx/dt) = (3/2)/(2t) = 3/(4t)
Answer: d²y/dx² = 3/(4t)