MathIsimple
Lesson 2.1: Pythagorean Theorem Derivation

Pythagorean Theorem Derivation

Journey through ancient mathematical wisdom and discover the elegant proof of one of geometry's most fundamental theorems.

Historical Context

The theorem that changed the world of mathematics

Ancient Origins

Pythagoras (c. 570-495 BCE): Greek mathematician and philosopher

While the theorem bears his name, evidence suggests it was known to ancient Babylonians and Egyptians centuries earlier.

Practical Applications:

  • • Egyptian pyramid construction
  • • Babylonian land surveying
  • • Ancient Chinese engineering
  • • Greek architecture and art

Modern Significance

Foundation of Geometry:

The theorem is fundamental to understanding distance, coordinate geometry, and trigonometric relationships.

Real-world Applications:

  • • GPS and navigation systems
  • • Computer graphics and gaming
  • • Engineering and construction
  • • Physics and astronomy

The Pythagorean Theorem

The fundamental relationship in right triangles

Visual Representation

Right Triangle with sides a, b, and hypotenuse c

Leg a:a
Leg b:b
Hypotenuse c:c

Theorem Statement

a² + b² = c²

In a right triangle, the square of the hypotenuse equals the sum of the squares of the other two sides.

Key Points:

  • • Only applies to right triangles (90° angle)
  • • c is always the longest side (hypotenuse)
  • • a and b are the two shorter sides (legs)
  • • The relationship is always true for any right triangle

Proof Methods

Multiple ways to prove this fundamental theorem

Visual Proof (Area Method)

Step 1: Create squares on each side

Draw squares with areas a², b², and c² on the three sides of the right triangle.

Step 2: Rearrange the pieces

The two smaller squares can be rearranged to exactly fill the larger square.

Conclusion:

Since the areas are equal, a² + b² = c²

Algebraic Proof

Step 1: Start with four identical triangles

Arrange four right triangles with legs a and b to form a large square.

Step 2: Calculate total area

Large square area = (a + b)² = a² + 2ab + b²

Step 3: Alternative calculation

Same area = 4 × (½ab) + c² = 2ab + c²

Conclusion:

a² + 2ab + b² = 2ab + c² → a² + b² = c²

Ancient Chinese Proof (Zhou Bi Suan Jing)

The "Gou Gu" theorem from ancient China (c. 1000 BCE)

Historical Context

Zhou Bi Suan Jing: "The Arithmetical Classic of the Gnomon and the Circular Paths of Heaven"

One of the oldest Chinese mathematical texts, dating back to the Zhou dynasty.

Gou Gu Theorem:

"Gou" (leg) and "Gu" (leg) refer to the two shorter sides of a right triangle.

Practical Use:

Used for astronomical calculations, land surveying, and construction projects.

Proof Method

Step 1: Create a square with side (a + b)

Place four right triangles with legs a and b in the corners.

Step 2: The inner space forms a square

The remaining area in the center is a square with side length c.

Step 3: Calculate areas

Total area = (a + b)² = 4 × (½ab) + c²

Result:

Simplifying: a² + 2ab + b² = 2ab + c² → a² + b² = c²

Advanced Proofs and Extensions

Explore different proof methods and extensions of the Pythagorean theorem

Algebraic Proof

Method: Using similar triangles

Create similar triangles within the right triangle

Steps:

1. Draw altitude from right angle to hypotenuse
2. Create two smaller similar triangles
3. Use similarity ratios to derive the theorem

Key Insight:

The altitude creates geometric mean relationships

Vector Proof

Method: Using vector dot products

Represent triangle sides as vectors

Key Formula:

|a + b|² = |a|² + |b|² + 2(a · b)

For Right Angles:

When a · b = 0, we get |a + b|² = |a|² + |b|²

Pythagorean Triples

Special sets of integers that satisfy the Pythagorean theorem

Primitive Triples

Definition:

Triples with no common factors

Examples:

(3, 4, 5), (5, 12, 13), (7, 24, 25)

Generating Formula

Euclid's Formula:

a = m² - n², b = 2mn, c = m² + n²

Conditions:

m > n > 0, gcd(m,n) = 1, m+n odd

Applications

Construction:

Creating right angles

Navigation:

Distance calculations

Practice Problems

Apply your understanding of the theorem

Problem 1: Find the Hypotenuse

Given: A right triangle with legs of length 3 and 4 units.

Find the length of the hypotenuse.

Solution:

Using a² + b² = c²:

3² + 4² = c²

9 + 16 = c²

25 = c²

c = √25 = 5

Answer: The hypotenuse is 5 units long.

Problem 2: Find a Missing Leg

Given: A right triangle with one leg of 5 units and hypotenuse of 13 units.

Find the length of the other leg.

Solution:

Using a² + b² = c²:

5² + b² = 13²

25 + b² = 169

b² = 169 - 25 = 144

b = √144 = 12

Answer: The other leg is 12 units long.

Ready for Applications?

Now that you understand the theorem's derivation, let's apply it to solve real-world problems.