MathIsimple
Lesson 4.1: Factoring Quadratic Equations

Master Factoring Methods for Quadratic Equations

Learn powerful factoring techniques to solve quadratic equations efficiently. Discover common factors, difference of squares, and trinomial factoring methods.

Learning Objectives

Factor out common factors from quadratic expressions
Recognize and factor difference of squares
Factor trinomials using various methods
Solve quadratic equations by factoring

Core Concepts

Standard Form of Quadratic Equation

A quadratic equation in standard form is: ax² + bx + c = 0 (where a ≠ 0)

a = coefficient of x² (quadratic coefficient)
b = coefficient of x (linear coefficient)
c = constant term

Factoring Strategy

Step 1: Look for common factors

Step 2: Check for difference of squares (a² - b²)

Step 3: Factor trinomials (ax² + bx + c)

Step 4: Set each factor equal to zero

Method 1: Common Factors

Example 1: Simple Common Factor

Solve: 2x² - 8x = 0

Step 1: Factor out the common factor 2x

2x² - 8x = 2x(x - 4)

Step 2: Set each factor equal to zero

2x = 0

x = 0

x - 4 = 0

x = 4

Solutions: x = 0 or x = 4

Example 2: Complex Common Factor

Solve: 3x² + 12x + 9 = 0

Step 1: Factor out the common factor 3

3x² + 12x + 9 = 3(x² + 4x + 3)

Step 2: Factor the trinomial inside parentheses

x² + 4x + 3 = (x + 1)(x + 3)

Step 3: Complete factorization

3(x + 1)(x + 3) = 0

Step 4: Solve each factor

x + 1 = 0

x = -1

x + 3 = 0

x = -3

Solutions: x = -1 or x = -3

Method 2: Difference of Squares

Pattern Recognition

Difference of squares: a² - b² = (a + b)(a - b)

Example 3: Basic Difference of Squares

Solve: x² - 16 = 0

Step 1: Recognize the pattern (perfect squares)

x² - 16 = x² - 4²

Step 2: Apply the difference of squares formula

x² - 4² = (x + 4)(x - 4)

Step 3: Set each factor equal to zero

x + 4 = 0

x = -4

x - 4 = 0

x = 4

Solutions: x = -4 or x = 4

Example 4: Advanced Difference of Squares

Solve: 9x² - 25 = 0

Step 1: Identify perfect squares

9x² - 25 = (3x)² - 5²

Step 2: Apply the formula

(3x)² - 5² = (3x + 5)(3x - 5)

Step 3: Solve each factor

3x + 5 = 0

x = -5/3

3x - 5 = 0

x = 5/3

Solutions: x = -5/3 or x = 5/3

Method 3: Trinomial Factoring

AC Method for ax² + bx + c

Step 1: Find two numbers that multiply to ac and add to b

Step 2: Rewrite the middle term using these numbers

Step 3: Factor by grouping

Example 5: Simple Trinomial

Solve: x² + 7x + 12 = 0

Step 1: Find two numbers that multiply to 12 and add to 7

3 × 4 = 12 and 3 + 4 = 7 ✓

Step 2: Factor the trinomial

x² + 7x + 12 = (x + 3)(x + 4)

Step 3: Set each factor equal to zero

x + 3 = 0

x = -3

x + 4 = 0

x = -4

Solutions: x = -3 or x = -4

Example 6: Complex Trinomial

Solve: 2x² + 11x + 5 = 0

Step 1: Find two numbers that multiply to 2×5=10 and add to 11

1 × 10 = 10 and 1 + 10 = 11 ✓

Step 2: Rewrite the middle term

2x² + 11x + 5 = 2x² + 1x + 10x + 5

Step 3: Factor by grouping

= x(2x + 1) + 5(2x + 1) = (x + 5)(2x + 1)

Step 4: Solve each factor

x + 5 = 0

x = -5

2x + 1 = 0

x = -1/2

Solutions: x = -5 or x = -1/2

Common Mistakes to Avoid

❌ Mistake 1: Forgetting to set factors equal to zero

After factoring (x + 3)(x - 2), don't forget to solve x + 3 = 0 and x - 2 = 0

❌ Mistake 2: Incorrect sign handling

When solving x - 4 = 0, remember to add 4 to both sides: x = 4 (not x = -4)

❌ Mistake 3: Not checking for common factors first

Always look for common factors before attempting other factoring methods

Advanced Factoring Techniques

Grouping Method

Example: 2x² + 6x + 3x + 9

= 2x(x + 3) + 3(x + 3)

= (2x + 3)(x + 3)

When to use: Four terms with common factors in pairs

Perfect Square Trinomials

Pattern: a² ± 2ab + b²

= (a ± b)²

Example: x² + 6x + 9 = (x + 3)²

Real-world Applications

Physics & Motion

Projectile Motion

h = -16t² + vt + h₀

Finding when object hits ground (h = 0)

Economics & Business

Profit Optimization

P = -x² + 100x - 500

Finding break-even points (P = 0)

Engineering & Design

Area Calculations

A = x(20 - x)

Optimizing rectangular areas

Practice Problems

Problem 1:

Solve: 4x² - 36 = 0

Show Solution

4x² - 36 = 4(x² - 9) = 4(x + 3)(x - 3) = 0

Solutions: x = -3 or x = 3

Problem 2:

Solve: x² - 5x + 6 = 0

Show Solution

x² - 5x + 6 = (x - 2)(x - 3) = 0

Solutions: x = 2 or x = 3

Problem 3:

Solve: 3x² - 12x = 0

Show Solution

3x² - 12x = 3x(x - 4) = 0

Solutions: x = 0 or x = 4