MathIsimple
Lesson 4.3: Graphing Quadratic Functions

Master Graphing Quadratic Functions

Discover the beautiful world of parabolas! Learn about vertices, axes of symmetry, and how to transform quadratic functions to create stunning graphs.

Learning Objectives

Identify key features of parabolas
Find vertex and axis of symmetry
Graph quadratic functions accurately
Understand transformations and their effects

Key Features of Parabolas

Standard Form: y = ax² + bx + c

Opening Direction

a > 0: Opens upward (∪)
a < 0: Opens downward (∩)

Width

|a| > 1: Narrower
|a| < 1: Wider

Y-Intercept

Point: (0, c)

Vertex

x = -b/(2a)
y = f(-b/(2a))

Vertex Form: y = a(x - h)² + k

Vertex Form Advantages

Vertex: (h, k) - directly visible!

Axis of Symmetry: x = h

Transformation: Easy to see shifts and stretches

Graphing: Start from vertex and plot points

Converting Standard to Vertex Form

Example: Convert y = 2x² - 8x + 5 to vertex form

Step 1: Factor out the coefficient of x²

y = 2(x² - 4x) + 5

Step 2: Complete the square

y = 2(x² - 4x + 4 - 4) + 5

y = 2((x - 2)² - 4) + 5

Step 3: Distribute and simplify

y = 2(x - 2)² - 8 + 5

y = 2(x - 2)² - 3

Result: Vertex form with vertex at (2, -3)

Step-by-Step Graphing Process

1

Find the vertex

Use x = -b/(2a) to find x-coordinate, then substitute to find y

2

Draw axis of symmetry

Vertical line through the vertex (x = vertex x-coordinate)

3

Find y-intercept

Substitute x = 0 to find (0, c)

4

Find x-intercepts

Set y = 0 and solve (if they exist)

5

Plot additional points

Use symmetry to find points on both sides of the axis

6

Draw the parabola

Connect points with a smooth curve

Example: Complete Graphing Process

Graph: y = x² - 4x + 3

Step 1: Find vertex

x = -(-4)/(2×1) = 4/2 = 2

y = (2)² - 4(2) + 3 = 4 - 8 + 3 = -1

Vertex: (2, -1)

Step 2: Axis of symmetry

x = 2

Step 3: Y-intercept

y = (0)² - 4(0) + 3 = 3

Y-intercept: (0, 3)

Step 4: X-intercepts

0 = x² - 4x + 3 = (x - 1)(x - 3)

X-intercepts: (1, 0) and (3, 0)

Step 5: Additional points (using symmetry)

Point (0, 3) has symmetric point (4, 3)

Additional point: (4, 3)

Graph Features:

  • • Opens upward (a = 1 > 0)
  • • Vertex at (2, -1)
  • • Axis of symmetry: x = 2
  • • X-intercepts at x = 1 and x = 3
  • • Y-intercept at (0, 3)

Transformations of Quadratic Functions

Horizontal Shifts

y = (x - h)²: Shift right by h units

y = (x + h)²: Shift left by h units

Vertical Shifts

y = x² + k: Shift up by k units

y = x² - k: Shift down by k units

Vertical Stretching/Compressing

y = ax² (|a| > 1): Vertical stretch

y = ax² (|a| < 1): Vertical compression

Reflection

y = -x²: Reflect over x-axis

y = -ax²: Reflect and stretch/compress

Combined Transformations Example

Function: y = -2(x - 3)² + 4

Reflection: Negative sign flips parabola downward

Vertical stretch: Factor of 2 makes it narrower

Horizontal shift: (x - 3) shifts right 3 units

Vertical shift: +4 shifts up 4 units

Final vertex: (3, 4)

Common Mistakes to Avoid

❌ Mistake 1: Wrong vertex formula

Remember: x-coordinate of vertex is -b/(2a), not b/(2a)

❌ Mistake 2: Confusing horizontal shifts

(x - h) shifts RIGHT, (x + h) shifts LEFT (opposite of what you might expect)

❌ Mistake 3: Not using symmetry

Use the axis of symmetry to find additional points efficiently

Practice Problems

Problem 1:

Find the vertex of y = x² - 6x + 8

Show Solution

x = -(-6)/(2×1) = 3

y = (3)² - 6(3) + 8 = 9 - 18 + 8 = -1

Vertex: (3, -1)

Problem 2:

Convert y = 3x² - 12x + 7 to vertex form

Show Solution

y = 3(x² - 4x) + 7

y = 3(x² - 4x + 4 - 4) + 7

y = 3((x - 2)² - 4) + 7

y = 3(x - 2)² - 12 + 7

y = 3(x - 2)² - 5

Problem 3:

Describe the transformations in y = -2(x + 1)² - 3

Show Solution

• Reflection over x-axis (negative sign)

• Vertical stretch by factor of 2

• Horizontal shift left 1 unit

• Vertical shift down 3 units

• Vertex: (-1, -3)