The essential toolkit: formulas for power, exponential, trigonometric, and inverse trigonometric functions.
Just as we memorize differentiation formulas, we need a collection of basic integration formulas. These are the building blocks for evaluating indefinite integrals. Each formula comes from reversing a corresponding differentiation rule.
For any real number :
For :
Verify by differentiation:
(a)
(b)
(c)
(d)
(e)
(a)
(b)
(c)
(d)
(a)
(b)
(c)
For :
(a)
(b)
(c)
Identify the form of the integrand. Look for: power functions (x^n), exponentials (e^x, a^x), trig functions, inverse trig patterns (1/√(1-x²), 1/(1+x²)), and logarithms (1/x).
The absolute value is needed because ln(x) is only defined for x > 0, but 1/x is defined for all x ≠ 0.
∫sin x dx = -cos x + C, but ∫sin(ax) dx = -cos(ax)/a + C. The chain rule in reverse requires dividing by a.
∫tan x dx = -ln|cos x| + C = ln|sec x| + C. ∫cot x dx = ln|sin x| + C.
∫sec x dx = ln|sec x + tan x| + C. ∫csc x dx = -ln|csc x + cot x| + C.
∫1/√(1-x²) dx = arcsin x + C. Usually arcsin is preferred.
∫1/√(a²-x²) dx = arcsin(x/a) + C. These generalize the basic formulas.
sinh x = (e^x - e^{-x})/2 and cosh x = (e^x + e^{-x})/2.
Wrong:
Right:
Wrong:
Right:
Wrong:
Right:
Wrong:
Right:
Problem:
Problem:
Write as:
Problem:
Problem:
Problem:
Problem:
Simplify:
Problem:
Here a = 5:
Problem:
Here a = 3:
Power, exponential, basic trig, and inverse trig forms.
Always check your answer by taking the derivative.
∫sin(ax)dx adds a factor of 1/a.
1/(1+x²) → arctan, 1/√(1-x²) → arcsin
Algebra often reveals a known form.
Practice until formulas are automatic.
Problem:
Problem:
Simplify:
Problem:
Problem:
Let u = 2x, so dx = du/2:
Problem:
Problem:
Here a = 5:
Problem:
Problem:
Simplify:
| f(x) | ∫f(x)dx | Notes |
|---|---|---|
| n ≠ -1 | ||
| x ≠ 0 | ||
| - | ||
| a > 0, a ≠ 1 | ||
| - | ||
| - | ||
| - | ||
| - | ||
| - | ||
| - | ||
| - | ||
| - | ||
| |x| < 1 | ||
| - | ||
| |x| < a | ||
| - | ||
| - | ||
| - |
Problem 1:
Problem 2:
Problem 3:
Problem 4:
Problem 5:
Problem 6:
Multiply by (sec x + tan x)/(sec x + tan x):
Let u = sec x + tan x, then du = (sec x tan x + sec²x) dx:
Write cot x = cos x / sin x. Let u = sin x, du = cos x dx:
Let x = a tan θ, then dx = a sec²θ dθ:
Since θ = arctan(x/a):
The integration formulas we use today were developed over centuries by mathematicians including Newton, Leibniz, Euler, and many others.
Leonhard Euler (1707-1783) made enormous contributions to integration, including the development of hyperbolic functions and their integrals.
The notation ∫ was introduced by Leibniz in 1675, representing an elongated “S” for “summa” (sum), reflecting the connection between integration and summation.
For , if , then:
Problem:
Problem:
Problem:
Problem:
Problem:
Problem:
Challenge 1:
Simplify:
Challenge 2:
Expand:
Challenge 3:
Simplify using sin²x + cos²x = 1:
Challenge 4:
Since 1 + tan²x = sec²x:
Challenge 5:
Write as
Problem: A particle has velocity v(t) = 3t² - 2t + 1. Find position s(t) if s(0) = 5.
Solution:
Using s(0) = 5: C = 5, so
Problem: Marginal cost is C'(x) = 100 + 0.5x. Find total cost if fixed costs are $2000.
Solution:
Using C(0) = 2000:
Problem: The rate of decay is dN/dt = -0.05N. Given N(0) = 1000, this is solved by:
The integral is used in the solution process.
Let u = √x, then x = u², dx = 2u du:
1.
2.
3.
4.
5.
6.
7.
8.
| Function | Derivative | Integral |
|---|---|---|
Problem:
Expand:
Problem:
Use:
Problem:
Complete:
Problem:
Problem:
Let u = cosh x, du = sinh x dx:
Problem:
Write:
Problem A:
Problem B:
Problem C:
Problem D:
Problem E:
Problem F:
(n ≠ -1)
,
arcsin: , arctan:
Always differentiate to check your answer