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Algebraic Structures

Algebraic structures form the language of modern mathematics. Understanding groups, rings, and fields is essential for linear algebra, where vector spaces are built on fields and linear maps preserve algebraic structure.

4-5 hours Foundational 10 Objectives
Learning Objectives
  • Define binary operations and verify their properties (closure, associativity, commutativity)
  • State the group axioms and determine whether a given set forms a group
  • Understand subgroups and apply the subgroup criterion
  • Define rings and distinguish between commutative rings and rings with unity
  • State the field axioms and recognize standard examples of fields
  • Define group homomorphisms and isomorphisms
  • Prove basic theorems about groups including uniqueness of identity and inverses
  • Understand the connection between algebraic structures and linear algebra
  • Work with finite fields and understand their importance
  • Apply Lagrange's theorem and understand cosets
Prerequisites
  • Basic set theory (sets, subsets, functions)
  • Familiarity with integers, rationals, and real numbers
  • Understanding of functions and their properties
  • Basic proof techniques (direct proof, contradiction)
  • Modular arithmetic (helpful but not required)
Historical Context

The study of algebraic structures emerged in the 19th century as mathematicians sought to understand the deep structure underlying number systems and polynomial equations.

Évariste Galois (1811-1832) introduced group theory to study when polynomial equations can be solved by radicals, founding what we now call Galois theory. His work, completed before his death at age 20, revolutionized algebra.

Richard Dedekind and Emmy Noether later developed ring and field theory into the abstract framework we use today. Noether's work in the 1920s established modern abstract algebra as a unified discipline.

1. Binary Operations

Before defining groups, rings, and fields, we need the fundamental concept of a binary operation. This is the basic building block of all algebraic structures.

Definition 1.1: Binary Operation

A binary operation on a set SS is a function :S×SS*: S \times S \to S that assigns to each ordered pair (a,b)S×S(a, b) \in S \times S a unique element abSa * b \in S.

Remark 1.1: Closure

The key point is that a binary operation on SS always produces elements in SS. We say SS is closed under the operation. For example, subtraction is not a binary operation on N\mathbb{N} because 25=3N2 - 5 = -3 \notin \mathbb{N}.

Example 1.1: Standard Binary Operations
  • Addition on Z\mathbb{Z}: (a,b)a+b(a, b) \mapsto a + b
  • Multiplication on R\mathbb{R}: (a,b)ab(a, b) \mapsto a \cdot b
  • Composition of functions: (f,g)fg(f, g) \mapsto f \circ g
  • Matrix multiplication on Mn(R)M_n(\mathbb{R})
  • Modular arithmetic: addition on Zn\mathbb{Z}_n
Definition 1.2: Properties of Binary Operations

Let * be a binary operation on SS.

  • Associativity: (ab)c=a(bc)(a * b) * c = a * (b * c) for all a,b,cSa, b, c \in S
  • Commutativity: ab=baa * b = b * a for all a,bSa, b \in S
  • Identity element: There exists eSe \in S such that ea=ae=ae * a = a * e = a for all aSa \in S
  • Inverse element: For each aSa \in S, there exists a1Sa^{-1} \in S such that aa1=a1a=ea * a^{-1} = a^{-1} * a = e
Example 1.2: Checking Properties

Matrix multiplication on M2(R)M_2(\mathbb{R}):

  • Associativity: (AB)C=A(BC)(AB)C = A(BC) always holds
  • Commutativity: ABBAAB \neq BA in general
  • Identity: I=(1001)I = \begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}
  • Inverses: Not all matrices have inverses (only invertible ones)
Theorem 1.1: Uniqueness of Identity

If a binary operation on SS has an identity element, then that identity is unique.

Proof:

Suppose ee and ee' are both identities. Then:

e=ee=ee = e * e' = e'

The first equality uses that ee' is an identity; the second uses that ee is an identity.

Theorem 1.2: Uniqueness of Inverses

In an associative operation with identity, if an element has an inverse, that inverse is unique.

Proof:

Let bb and cc both be inverses of aa. Then:

b=be=b(ac)=(ba)c=ec=cb = b * e = b * (a * c) = (b * a) * c = e * c = c

2. Groups

Groups are the simplest algebraic structures with a rich theory. They capture the essence of symmetry and appear throughout mathematics, from number theory to geometry to physics.

Definition 2.1: Group

A group is a set GG together with a binary operation :G×GG*: G \times G \to G satisfying:

  • (G1) Associativity: (ab)c=a(bc)(a * b) * c = a * (b * c) for all a,b,cGa, b, c \in G
  • (G2) Identity: There exists eGe \in G with ea=ae=ae * a = a * e = a for all aGa \in G
  • (G3) Inverses: For each aGa \in G, there exists a1Ga^{-1} \in G with aa1=a1a=ea * a^{-1} = a^{-1} * a = e

If additionally ab=baa * b = b * a for all a,bGa, b \in G, we call GG an abelian group.

Example 2.1: Standard Examples of Groups
  • (Z,+)(\mathbb{Z}, +) — integers under addition (abelian, infinite)
  • (Q,)(\mathbb{Q}^*, \cdot) — nonzero rationals under multiplication (abelian)
  • (Zn,+)(\mathbb{Z}_n, +) — integers mod nn under addition (abelian, finite)
  • (Sn,)(S_n, \circ) — permutations of nn elements (non-abelian for n3n \geq 3)
  • (GLn(R),)(GL_n(\mathbb{R}), \cdot) — invertible matrices (non-abelian for n2n \geq 2)
Example 2.2: The Symmetric Group S₃

The symmetric group S3S_3 consists of all permutations of {1,2,3}\{1, 2, 3\}. It has 6 elements:

S3={e,(12),(13),(23),(123),(132)}S_3 = \{e, (12), (13), (23), (123), (132)\}

This is the smallest non-abelian group. For example, (12)(13)=(132)(12)(13) = (132) but (13)(12)=(123)(13)(12) = (123).

Theorem 2.1: Basic Group Properties

Let GG be a group. Then:

  1. The identity element is unique
  2. Each element has a unique inverse
  3. (a1)1=a(a^{-1})^{-1} = a for all aGa \in G
  4. (ab)1=b1a1(ab)^{-1} = b^{-1}a^{-1} for all a,bGa, b \in G
  5. If ab=acab = ac, then b=cb = c (left cancellation)
  6. If ba=caba = ca, then b=cb = c (right cancellation)
Proof of Theorem 2.1 (Property 4):

We verify that b1a1b^{-1}a^{-1} is the inverse of abab:

(ab)(b1a1)=a(bb1)a1=aea1=aa1=e(ab)(b^{-1}a^{-1}) = a(bb^{-1})a^{-1} = aea^{-1} = aa^{-1} = e

Similarly, (b1a1)(ab)=e(b^{-1}a^{-1})(ab) = e.

Definition 2.2: Order of an Element

The order of an element aGa \in G, denoted ord(a)\text{ord}(a) or a|a|, is the smallest positive integer nn such that an=ea^n = e. If no such nn exists, we say aa has infinite order.

Example 2.3: Orders in ℤ₆

In (Z6,+)(\mathbb{Z}_6, +):

  • 0=1|0| = 1 (identity)
  • 1=5=6|1| = |5| = 6
  • 2=4=3|2| = |4| = 3 (since 2+2+2=602 + 2 + 2 = 6 \equiv 0)
  • 3=2|3| = 2 (since 3+3=603 + 3 = 6 \equiv 0)
Definition 2.3: Cyclic Group

A group GG is cyclic if there exists an element gGg \in G such that every element of GG can be written as gng^n for some nZn \in \mathbb{Z}. The element gg is called a generator.

Example 2.4: Cyclic Groups
  • Z\mathbb{Z} is cyclic with generator 1 (or -1)
  • Zn\mathbb{Z}_n is cyclic with generator 1
  • Z6\mathbb{Z}_6 has generators 1 and 5
  • The Klein four-group is NOT cyclic (no element of order 4)

3. Subgroups

Subgroups allow us to study the internal structure of groups. They are fundamental to understanding group homomorphisms and quotient groups.

Definition 3.1: Subgroup

Let (G,)(G, *) be a group. A subset HGH \subseteq G is a subgroupof GG, written HGH \leq G, if (H,)(H, *) is itself a group.

Theorem 3.1: Subgroup Criterion (One-Step)

A nonempty subset HGH \subseteq G is a subgroup if and only if for all a,bHa, b \in H, we have ab1Hab^{-1} \in H.

Proof:

(⇒) If HH is a subgroup, then b1Hb^{-1} \in H and ab1Hab^{-1} \in H by closure.

(⇐) Suppose the condition holds. We verify:

  • Identity: Pick any aHa \in H. Then e=aa1He = aa^{-1} \in H.
  • Inverses: For aHa \in H, a1=ea1Ha^{-1} = ea^{-1} \in H.
  • Closure: For a,bHa, b \in H, ab=a(b1)1Hab = a(b^{-1})^{-1} \in H.

Associativity is inherited from GG.

Theorem 3.2: Subgroup Criterion (Two-Step)

A nonempty subset HGH \subseteq G is a subgroup if and only if:

  1. For all a,bHa, b \in H, abHab \in H (closure)
  2. For all aHa \in H, a1Ha^{-1} \in H (inverses)
Example 3.1: Subgroups of ℤ

The subgroups of (Z,+)(\mathbb{Z}, +) are exactly nZ={nk:kZ}n\mathbb{Z} = \{nk : k \in \mathbb{Z}\}for n0n \geq 0:

  • 0Z={0}0\mathbb{Z} = \{0\} (trivial subgroup)
  • 1Z=Z1\mathbb{Z} = \mathbb{Z}
  • 2Z={,4,2,0,2,4,}2\mathbb{Z} = \{\ldots, -4, -2, 0, 2, 4, \ldots\} (even integers)
  • 3Z={,6,3,0,3,6,}3\mathbb{Z} = \{\ldots, -6, -3, 0, 3, 6, \ldots\}
Theorem 3.3: Lagrange's Theorem

If HH is a subgroup of a finite group GG, then H|H| divides G|G|.

Corollary 3.1

The order of any element in a finite group divides the order of the group.

Example 3.2: Applying Lagrange's Theorem

In a group of order 12, possible subgroup orders are 1, 2, 3, 4, 6, 12. Possible element orders are also divisors of 12.

Definition 3.2: Cosets

Let HGH \leq G and gGg \in G. The left coset of HHcontaining gg is:

gH={gh:hH}gH = \{gh : h \in H\}

Similarly, the right coset is Hg={hg:hH}Hg = \{hg : h \in H\}.

Theorem 3.4: Coset Properties

Let HGH \leq G. Then:

  1. Every coset has the same cardinality as HH
  2. Two cosets are either equal or disjoint
  3. The cosets partition GG
  4. aH=bHaH = bH iff a1bHa^{-1}b \in H
Definition 3.3: Normal Subgroup

A subgroup HGH \leq G is normal, written HGH \trianglelefteq G, if gH=HggH = Hg for all gGg \in G.

Equivalently: gHg1=HgHg^{-1} = H for all gGg \in G.

Example 3.3: Normal Subgroups
  • Every subgroup of an abelian group is normal
  • {e}\{e\} and GG are always normal subgroups
  • AnSnA_n \trianglelefteq S_n (alternating group is normal in symmetric group)
  • The kernel of any homomorphism is a normal subgroup
Theorem 3.5: Quotient Group

If HGH \trianglelefteq G, then the set of cosets G/H={gH:gG}G/H = \{gH : g \in G\}forms a group under the operation (aH)(bH)=(ab)H(aH)(bH) = (ab)H.

4. Rings

Rings generalize the integers by combining addition and multiplication. They are essential for understanding polynomial rings and matrix algebras.

Definition 4.1: Ring

A ring is a set RR with two binary operations ++ (addition) and \cdot (multiplication) such that:

  • (R1) (R,+)(R, +) is an abelian group
  • (R2) Multiplication is associative: (ab)c=a(bc)(ab)c = a(bc)
  • (R3) Distributive laws: a(b+c)=ab+aca(b + c) = ab + ac and (a+b)c=ac+bc(a + b)c = ac + bc
Definition 4.2: Special Rings
  • Ring with unity: Has multiplicative identity 11
  • Commutative ring: ab=baab = ba for all a,ba, b
  • Integral domain: Commutative ring with unity, no zero divisors
  • Division ring: Every nonzero element has multiplicative inverse
Example 4.1: Standard Examples of Rings
  • (Z,+,)(\mathbb{Z}, +, \cdot) — commutative ring with unity, integral domain
  • (Zn,+,)(\mathbb{Z}_n, +, \cdot) — commutative ring with unity
  • Mn(R)M_n(\mathbb{R}) — non-commutative ring with unity
  • F[x]F[x] — polynomial ring, commutative with unity
  • 2Z2\mathbb{Z} — commutative ring without unity
Theorem 4.1: Ring Properties

In any ring RR:

  1. a0=0a=0a \cdot 0 = 0 \cdot a = 0 for all aRa \in R
  2. a(b)=(a)b=(ab)a(-b) = (-a)b = -(ab)
  3. (a)(b)=ab(-a)(-b) = ab
  4. If RR has unity, then (1)a=a(-1)a = -a
Proof of Theorem 4.1 (Property 1):
a0=a(0+0)=a0+a0a \cdot 0 = a(0 + 0) = a \cdot 0 + a \cdot 0

Adding a0-a \cdot 0 to both sides gives 0=a00 = a \cdot 0.

Definition 4.3: Zero Divisors

An element a0a \neq 0 in a ring is a zero divisor if there exists b0b \neq 0 such that ab=0ab = 0 or ba=0ba = 0.

Example 4.2: Zero Divisors in ℤ₆

In Z6\mathbb{Z}_6: 23=602 \cdot 3 = 6 \equiv 0.

So 2 and 3 are zero divisors. In fact, Zn\mathbb{Z}_n has zero divisors if and only if nn is composite.

5. Fields

Fields are the scalars of linear algebra. Vector spaces are always defined over a field, so understanding fields is essential for understanding vector spaces.

Definition 5.1: Field

A field is a set FF with operations ++ and \cdot such that:

  • (F1) (F,+)(F, +) is an abelian group with identity 00
  • (F2) (F{0},)(F \setminus \{0\}, \cdot) is an abelian group with identity 11
  • (F3) Distributivity: a(b+c)=ab+aca(b + c) = ab + ac
  • (F4) 010 \neq 1
Remark 5.1: Field vs Ring

A field is a commutative ring with unity where every nonzero element has a multiplicative inverse. Equivalently, a field is a commutative division ring.

Example 5.1: Standard Fields
  • Q\mathbb{Q} — rational numbers
  • R\mathbb{R} — real numbers
  • C\mathbb{C} — complex numbers
  • Zp\mathbb{Z}_p for prime pp — finite field with pp elements
  • Q(2)={a+b2:a,bQ}\mathbb{Q}(\sqrt{2}) = \{a + b\sqrt{2} : a, b \in \mathbb{Q}\}
Theorem 5.1: ℤₚ is a Field

Zp\mathbb{Z}_p is a field if and only if pp is prime.

Proof:

(⇒) If pp is composite, say p=abp = ab with 1<a,b<p1 < a, b < p, then aa and bb are zero divisors, so Zp\mathbb{Z}_p is not a field.

(⇐) If pp is prime and a≢0a \not\equiv 0, then gcd(a,p)=1\gcd(a, p) = 1. By Bézout's identity, there exist x,yx, y with ax+py=1ax + py = 1, so ax1(modp)ax \equiv 1 \pmod{p}. Thus aa has inverse xx.

Definition 5.2: Characteristic of a Field

The characteristic of a field FF, denoted char(F)\text{char}(F), is the smallest positive integer nn such that 1+1++1n times=0\underbrace{1 + 1 + \cdots + 1}_{n \text{ times}} = 0. If no such nn exists, char(F)=0\text{char}(F) = 0.

Theorem 5.2: Characteristic Properties

The characteristic of a field is either 0 or a prime number.

Example 5.2: Characteristics
  • char(Q)=char(R)=char(C)=0\text{char}(\mathbb{Q}) = \text{char}(\mathbb{R}) = \text{char}(\mathbb{C}) = 0
  • char(Zp)=p\text{char}(\mathbb{Z}_p) = p
Definition 5.3: Finite Fields

A finite field (or Galois field) is a field with finitely many elements. The number of elements is always pnp^n for some prime pp and positive integer nn.

We write Fpn\mathbb{F}_{p^n} or GF(pn)GF(p^n) for the unique field of order pnp^n.

Theorem 5.3: Finite Field Existence and Uniqueness

For every prime power pnp^n:

  1. There exists a field with exactly pnp^n elements
  2. Any two fields of order pnp^n are isomorphic
  3. The multiplicative group Fpn\mathbb{F}_{p^n}^* is cyclic of order pn1p^n - 1
Example 5.3: Common Finite Fields
  • F2={0,1}\mathbb{F}_2 = \{0, 1\} — used in computer science (binary)
  • F3={0,1,2}\mathbb{F}_3 = \{0, 1, 2\}
  • F4\mathbb{F}_4 — has 4 elements, but NOT Z4\mathbb{Z}_4 (which has zero divisors)
  • F256=F28\mathbb{F}_{256} = \mathbb{F}_{2^8} — used in AES encryption
Remark 5.2: Applications of Finite Fields

Finite fields are essential in:

  • Cryptography: AES, elliptic curve cryptography
  • Error-correcting codes: Reed-Solomon codes
  • Computer graphics: GF(2) arithmetic
  • Combinatorics: Latin squares, block designs

6. Homomorphisms and Isomorphisms

Homomorphisms are structure-preserving maps between algebraic structures. They allow us to compare and relate different groups, rings, and fields.

Definition 6.1: Group Homomorphism

Let (G,)(G, *) and (H,)(H, \circ) be groups. A function ϕ:GH\phi: G \to H is a group homomorphism if:

ϕ(ab)=ϕ(a)ϕ(b)for all a,bG\phi(a * b) = \phi(a) \circ \phi(b) \quad \text{for all } a, b \in G
Theorem 6.1: Properties of Homomorphisms

If ϕ:GH\phi: G \to H is a group homomorphism, then:

  1. ϕ(eG)=eH\phi(e_G) = e_H
  2. ϕ(a1)=ϕ(a)1\phi(a^{-1}) = \phi(a)^{-1} for all aGa \in G
  3. ϕ(an)=ϕ(a)n\phi(a^n) = \phi(a)^n for all nZn \in \mathbb{Z}
Proof of Theorem 6.1 (Property 1):
ϕ(eG)=ϕ(eGeG)=ϕ(eG)ϕ(eG)\phi(e_G) = \phi(e_G \cdot e_G) = \phi(e_G) \circ \phi(e_G)

Multiplying both sides by ϕ(eG)1\phi(e_G)^{-1} gives eH=ϕ(eG)e_H = \phi(e_G).

Definition 6.2: Kernel and Image

For a homomorphism ϕ:GH\phi: G \to H:

  • Kernel: ker(ϕ)={gG:ϕ(g)=eH}\ker(\phi) = \{g \in G : \phi(g) = e_H\}
  • Image: im(ϕ)={ϕ(g):gG}\text{im}(\phi) = \{\phi(g) : g \in G\}
Theorem 6.2: Kernel and Image are Subgroups

If ϕ:GH\phi: G \to H is a homomorphism, then ker(ϕ)G\ker(\phi) \leq G and im(ϕ)H\text{im}(\phi) \leq H.

Definition 6.3: Isomorphism

A homomorphism ϕ:GH\phi: G \to H is an isomorphism if it is bijective. We write GHG \cong H if such an isomorphism exists.

Theorem 6.3: Injectivity via Kernel

A homomorphism ϕ:GH\phi: G \to H is injective if and only if ker(ϕ)={eG}\ker(\phi) = \{e_G\}.

Example 6.1: Isomorphism Example

Consider ϕ:(R,+)(R+,)\phi: (\mathbb{R}, +) \to (\mathbb{R}^+, \cdot) defined by ϕ(x)=ex\phi(x) = e^x.

  • Homomorphism: ex+y=exeye^{x+y} = e^x \cdot e^y
  • Bijective: ϕ1(y)=ln(y)\phi^{-1}(y) = \ln(y)

Thus (R,+)(R+,)(\mathbb{R}, +) \cong (\mathbb{R}^+, \cdot).

Example 6.2: Non-Isomorphic Groups

(Z4,+)(\mathbb{Z}_4, +) and (Z2×Z2,+)(\mathbb{Z}_2 \times \mathbb{Z}_2, +) are both groups of order 4, but they are NOT isomorphic.

Proof: Z4\mathbb{Z}_4 is cyclic (generated by 1), but Z2×Z2\mathbb{Z}_2 \times \mathbb{Z}_2 has no element of order 4.

Theorem 6.4: First Isomorphism Theorem

If ϕ:GH\phi: G \to H is a group homomorphism, then:

G/ker(ϕ)im(ϕ)G / \ker(\phi) \cong \text{im}(\phi)
Remark 6.1: Ring and Field Homomorphisms

Ring homomorphisms preserve both operations: ϕ(a+b)=ϕ(a)+ϕ(b)\phi(a + b) = \phi(a) + \phi(b) and ϕ(ab)=ϕ(a)ϕ(b)\phi(ab) = \phi(a)\phi(b).

Field homomorphisms are always injective (nonzero kernel would give zero divisors).

Definition 6.4: Automorphism

An automorphism is an isomorphism from a group to itself. The set of all automorphisms of GG, denoted Aut(G)\text{Aut}(G), forms a group under composition.

Example 6.3: Automorphisms of ℤ

Aut(Z)={id,id}Z2\text{Aut}(\mathbb{Z}) = \{\text{id}, -\text{id}\} \cong \mathbb{Z}_2.

Only ϕ(n)=n\phi(n) = n and ϕ(n)=n\phi(n) = -n preserve the group structure.

7. Connection to Linear Algebra

Algebraic structures are not just prerequisites—they are the foundation of linear algebra.

  • Vector spaces are abelian groups under addition, with scalar multiplication from a field.
  • Linear maps are group homomorphisms that also preserve scalar multiplication.
  • Matrix rings Mn(F)M_n(F) are non-commutative rings with deep connections to linear transformations.
  • Determinant is a group homomorphism from GLn(F)GL_n(F) to FF^*.
  • Eigenvalues may require field extensions to find.
Example 7.1: Vector Spaces as Abelian Groups

Every vector space VV over a field FF satisfies:

  • (V,+)(V, +) is an abelian group
  • Scalar multiplication distributes: α(u+v)=αu+αv\alpha(u + v) = \alpha u + \alpha v
  • The field structure ensures: (α+β)v=αv+βv(\alpha + \beta)v = \alpha v + \beta v
Example 7.2: The General Linear Group

The general linear group GLn(F)GL_n(F) consists of all invertible n×nn \times n matrices over FF. It is:

  • A group under matrix multiplication
  • Non-abelian for n2n \geq 2
  • The automorphism group of FnF^n
Remark 7.1: Why Fields Matter

The choice of field affects linear algebra fundamentally:

  • C\mathbb{C} is algebraically closed—every polynomial has roots
  • R\mathbb{R} is not—some matrices have no real eigenvalues
  • Finite fields Fp\mathbb{F}_p are essential in coding theory

8. Worked Examples

Example 8.1: Verifying a Group

Problem: Show that (Q{1},)(\mathbb{Q} \setminus \{-1\}, *) with ab=a+b+aba * b = a + b + ab is a group.

Solution:

  • Closure: If a,b1a, b \neq -1, then ab=a+b+ab1a * b = a + b + ab \neq -1(since ab=1a * b = -1 implies (1+a)(1+b)=0(1+a)(1+b) = 0)
  • Associativity: (ab)c=a(bc)(a * b) * c = a * (b * c) (verify by expansion)
  • Identity: a0=a+0+0=aa * 0 = a + 0 + 0 = a, so e=0e = 0
  • Inverse: ax=0x=a/(1+a)a * x = 0 \Rightarrow x = -a/(1+a)
Example 8.2: Finding Subgroups

Problem: Find all subgroups of Z12\mathbb{Z}_{12}.

Solution: By Lagrange, subgroup orders divide 12.

  • Order 1: {0}\{0\}
  • Order 2: {0,6}\{0, 6\}
  • Order 3: {0,4,8}\{0, 4, 8\}
  • Order 4: {0,3,6,9}\{0, 3, 6, 9\}
  • Order 6: {0,2,4,6,8,10}\{0, 2, 4, 6, 8, 10\}
  • Order 12: Z12\mathbb{Z}_{12}
Example 8.3: Ring Homomorphism

Problem: Show that ϕ:ZZn\phi: \mathbb{Z} \to \mathbb{Z}_ndefined by ϕ(a)=amodn\phi(a) = a \mod n is a ring homomorphism.

Solution:

ϕ(a+b)=(a+b)modn=(amodn)+(bmodn)=ϕ(a)+ϕ(b)\phi(a + b) = (a + b) \mod n = (a \mod n) + (b \mod n) = \phi(a) + \phi(b)
ϕ(ab)=(ab)modn=(amodn)(bmodn)=ϕ(a)ϕ(b)\phi(ab) = (ab) \mod n = (a \mod n)(b \mod n) = \phi(a)\phi(b)
Example 8.4: Field Construction

Problem: Verify that Z5\mathbb{Z}_5 is a field.

Solution: Since 5 is prime, we check multiplicative inverses:

  • 11=11^{-1} = 1 (since 11=11 \cdot 1 = 1)
  • 21=32^{-1} = 3 (since 23=612 \cdot 3 = 6 \equiv 1)
  • 31=23^{-1} = 2 (since 32=613 \cdot 2 = 6 \equiv 1)
  • 41=44^{-1} = 4 (since 44=1614 \cdot 4 = 16 \equiv 1)
Example 8.5: Order of Elements

Problem: Find the order of each element in Z8\mathbb{Z}_8^*.

Solution: Z8={1,3,5,7}\mathbb{Z}_8^* = \{1, 3, 5, 7\}

  • 1=1|1| = 1
  • 3=2|3| = 2 since 32=913^2 = 9 \equiv 1
  • 5=2|5| = 2 since 52=2515^2 = 25 \equiv 1
  • 7=2|7| = 2 since 72=4917^2 = 49 \equiv 1
Example 8.6: Kernel Computation

Problem: Find ker(ϕ)\ker(\phi) where ϕ:ZZ12\phi: \mathbb{Z} \to \mathbb{Z}_{12}with ϕ(n)=nmod12\phi(n) = n \mod 12.

Solution:

ker(ϕ)={nZ:n0(mod12)}=12Z\ker(\phi) = \{n \in \mathbb{Z} : n \equiv 0 \pmod{12}\} = 12\mathbb{Z}
Example 8.7: Showing Not a Group

Problem: Is (Z,)(\mathbb{Z}, -) a group under subtraction?

Solution: No. Subtraction is not associative:

(53)2=05(32)=4(5 - 3) - 2 = 0 \neq 5 - (3 - 2) = 4

Since (ab)ca(bc)(a - b) - c \neq a - (b - c) in general, this fails the group axioms.

Example 8.8: Cyclic Group Generator

Problem: Which elements generate Z10\mathbb{Z}_{10}?

Solution: An element aa generates Zn\mathbb{Z}_niff gcd(a,n)=1\gcd(a, n) = 1.

For n=10n = 10: generators are {1,3,7,9}\{1, 3, 7, 9\} (4 generators).

In general, the number of generators is ϕ(n)\phi(n) (Euler's totient function).

Example 8.9: Polynomial Ring

Problem: Show that x2+1x^2 + 1 is irreducible in R[x]\mathbb{R}[x]but factors in C[x]\mathbb{C}[x].

Solution:

  • In R[x]\mathbb{R}[x]: x2+1=0x^2 + 1 = 0 has no real roots, so it's irreducible
  • In C[x]\mathbb{C}[x]: x2+1=(xi)(x+i)x^2 + 1 = (x - i)(x + i)

This shows why field extensions matter for factorization.

Example 8.10: Coset Calculation

Problem: Find the cosets of H={0,4,8}H = \{0, 4, 8\} in Z12\mathbb{Z}_{12}.

Solution: H=3|H| = 3, so there are 12/3=412/3 = 4 cosets:

  • 0+H={0,4,8}0 + H = \{0, 4, 8\}
  • 1+H={1,5,9}1 + H = \{1, 5, 9\}
  • 2+H={2,6,10}2 + H = \{2, 6, 10\}
  • 3+H={3,7,11}3 + H = \{3, 7, 11\}

9. Common Mistakes

Mistake 1: Assuming all rings have unity

Not all rings have a multiplicative identity. For example, 2Z2\mathbb{Z} is a ring without unity.

Mistake 2: Forgetting that ℤₙ may have zero divisors

Zn\mathbb{Z}_n has zero divisors when nn is composite. Only Zp\mathbb{Z}_p for prime pp is a field.

Mistake 3: Assuming commutativity

Matrix multiplication is not commutative. The general linear group GLnGL_n is non-abelian for n2n \geq 2.

Mistake 4: Confusing subgroup order with element order

Lagrange says subgroup orders divide group order. Element orders also divide group order, but not every divisor is necessarily an element order.

Mistake 5: Wrong inverse formula in non-abelian groups

In non-abelian groups, (ab)1=b1a1(ab)^{-1} = b^{-1}a^{-1}, NOT a1b1a^{-1}b^{-1}.

10. Key Takeaways

Groups

One operation with associativity, identity, and inverses. Foundation of symmetry.

Rings

Two operations with abelian group for addition, associative multiplication, and distributivity.

Fields

Commutative rings where every nonzero element has a multiplicative inverse. Scalars of linear algebra.

Homomorphisms

Structure-preserving maps. Kernel measures failure of injectivity. Isomorphisms show structural equivalence.

Algebraic Structures Practice
12
Questions
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Correct
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Accuracy
1
Which of the following is NOT a group under addition?
Easy
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2
What is the identity element in the group (Z,+)(\mathbb{Z}, +)?
Easy
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3
Is (Z,)(\mathbb{Z}, \cdot) a group under multiplication?
Medium
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4
In the group Z6\mathbb{Z}_6 under addition modulo 6, what is the inverse of 4?
Easy
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5
Which of the following is a field?
Medium
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6
Let H={0,2,4}H = \{0, 2, 4\} in Z6\mathbb{Z}_6. Is HH a subgroup of (Z6,+)(\mathbb{Z}_6, +)?
Hard
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7
If GG is a group with G=12|G| = 12, what are the possible orders of subgroups?
Medium
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8
A ring must have which of the following?
Medium
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9
What is the characteristic of the field Z5\mathbb{Z}_5?
Medium
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10
If ϕ:GH\phi: G \to H is a group homomorphism and eHe_H is the identity in HH, then ker(ϕ)=?\ker(\phi) = ?
Hard
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11
Which statement about fields is FALSE?
Hard
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12
The group (Z4,+)(\mathbb{Z}_4, +) is isomorphic to which of the following?
Hard
Not attempted

Frequently Asked Questions

What's the difference between a group and a monoid?

A monoid has closure, associativity, and an identity element. A group has all of these plus inverses. For example, (ℕ, +) is a monoid (identity is 0) but not a group (no additive inverses for positive numbers).

Why study abstract algebraic structures?

Abstract structures reveal common patterns across mathematics. Once you prove something for all groups, it applies to integers under addition, matrices under multiplication, permutations, and more. This abstraction is the foundation of modern mathematics.

What's the relationship between groups and symmetry?

Every symmetry group is literally a group! The symmetries of a square form a group (the dihedral group D₄). Group theory was essentially born from studying symmetries of polynomial equations (Galois theory).

Why do fields need two operations?

Fields model number systems where you can add, subtract, multiply, and divide. You need addition for combining quantities and multiplication for scaling. The two operations must interact via distributivity to work coherently.

Is every ring with division a field?

Almost! A ring where every nonzero element has a multiplicative inverse is called a division ring (or skew field). If multiplication is also commutative, it's a field. The quaternions form a division ring that is not a field.

Why are finite fields important?

Finite fields are crucial in coding theory, cryptography, and computer science. Error-correcting codes like Reed-Solomon codes use finite fields. Modern encryption systems (like AES) rely on arithmetic in finite fields.

What does 'characteristic' mean for a field?

The characteristic is the smallest positive integer n such that 1 + 1 + ... + 1 (n times) = 0. For ℚ, ℝ, ℂ, this never happens, so they have characteristic 0. For ℤₚ, the characteristic is p.

Can a group be infinite?

Yes! (ℤ, +) is an infinite group. (ℝ, +) and (ℂ \ {0}, ×) are also infinite groups. Finite groups have special properties (Lagrange's theorem), but infinite groups are equally important.

What's the connection between algebraic structures and linear algebra?

Vector spaces are defined over fields, linear maps preserve group structure, determinants relate to field properties, and eigenvalues live in field extensions. Understanding algebraic structures makes linear algebra concepts clearer and more general.

How do homomorphisms help us understand structure?

Homomorphisms are structure-preserving maps that let us compare algebraic objects. The kernel measures 'how far' from being injective. Isomorphisms show when two seemingly different structures are 'the same' algebraically.