MathIsimple
LA-1.2
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Complex Numbers

Complex numbers extend the reals to ensure every polynomial has roots. They are indispensable for spectral theory in linear algebra—eigenvalues of real matrices may be complex, and the spectral theorem is most elegant over ℂ.

3-4 hours Foundation Level 10 Objectives
Learning Objectives
  • Construct the complex numbers algebraically as ordered pairs
  • Convert between rectangular and polar forms
  • Apply Euler's formula for complex exponentials
  • Use De Moivre's theorem to compute powers
  • Find all nth roots of complex numbers
  • Understand why ℂ is algebraically closed
  • Apply complex conjugates to simplify expressions
  • Prove basic properties using complex number algebra
  • Understand the geometric interpretation of complex operations
  • Apply complex numbers to solve polynomial equations
Prerequisites
  • Field axioms from LA-1.1 (Algebraic Structures)
  • Trigonometric functions (sine, cosine, tangent)
  • Basic properties of exponential functions
  • Polar coordinates (helpful but not required)
  • Quadratic formula and polynomial roots
Historical Context

Complex numbers emerged from attempts to solve polynomial equations. In the 16th century, Cardano and Bombelli encountered square roots of negative numbers while solving cubic equations—even for equations with real solutions!

Euler (18th century) introduced the notation ii for 1\sqrt{-1}and discovered the remarkable formula eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta.

Gauss gave the first rigorous proofs of the Fundamental Theorem of Algebra and popularized the geometric interpretation of complex numbers as points in a plane. Hamilton later provided the formal construction as ordered pairs.

1. Algebraic Construction of ℂ

We can construct the complex numbers rigorously as ordered pairs of real numbers with specially defined operations. This shows that C\mathbb{C} is not mysterious—it's simply R2\mathbb{R}^2 with a clever multiplication.

Definition 1.1: Complex Numbers

The complex numbers C\mathbb{C} is the set R×R\mathbb{R} \times \mathbb{R} with operations:

  • Addition: (a,b)+(c,d)=(a+c,b+d)(a, b) + (c, d) = (a + c, b + d)
  • Multiplication: (a,b)(c,d)=(acbd,ad+bc)(a, b) \cdot (c, d) = (ac - bd, ad + bc)

We write i=(0,1)i = (0, 1) and identify aRa \in \mathbb{R} with (a,0)C(a, 0) \in \mathbb{C}. Then (a,b)=a+bi(a, b) = a + bi.

Theorem 1.1: ℂ is a Field

(C,+,)(\mathbb{C}, +, \cdot) as defined above is a field with:

  • Additive identity: 0=(0,0)0 = (0, 0)
  • Multiplicative identity: 1=(1,0)1 = (1, 0)
  • Additive inverse of (a,b)(a, b): (a,b)(-a, -b)
  • Multiplicative inverse of (a,b)0(a, b) \neq 0: (aa2+b2,ba2+b2)\left(\frac{a}{a^2+b^2}, \frac{-b}{a^2+b^2}\right)
Proof of Theorem 1.1:

Most axioms follow from direct calculation. The key is the multiplicative inverse. For z=(a,b)(0,0)z = (a, b) \neq (0, 0), we need zw=1z \cdot w = 1.

Let w=(c,d)w = (c, d). Then:

(a,b)(c,d)=(acbd,ad+bc)=(1,0)(a, b) \cdot (c, d) = (ac - bd, ad + bc) = (1, 0)

This gives the system:

acbd=1,ad+bc=0ac - bd = 1, \quad ad + bc = 0

Solving: c=aa2+b2c = \frac{a}{a^2 + b^2}, d=ba2+b2d = \frac{-b}{a^2 + b^2}.

This is well-defined since a2+b2>0a^2 + b^2 > 0 when (a,b)(0,0)(a, b) \neq (0, 0).

Remark 1.1: The Imaginary Unit

Note that i2=(0,1)(0,1)=(0011,01+10)=(1,0)=1i^2 = (0, 1) \cdot (0, 1) = (0 \cdot 0 - 1 \cdot 1, 0 \cdot 1 + 1 \cdot 0) = (-1, 0) = -1.

This is the defining property: we have constructed a field containing R\mathbb{R} in which x2+1=0x^2 + 1 = 0 has a solution.

Example 1.4: Complex Arithmetic

Compute (2+3i)+(4i)(2 + 3i) + (4 - i) and (2+3i)(4i)(2 + 3i)(4 - i).

Addition:

(2+3i)+(4i)=(2+4)+(31)i=6+2i(2 + 3i) + (4 - i) = (2 + 4) + (3 - 1)i = 6 + 2i

Multiplication:

(2+3i)(4i)=82i+12i3i2=8+10i+3=11+10i(2 + 3i)(4 - i) = 8 - 2i + 12i - 3i^2 = 8 + 10i + 3 = 11 + 10i
Theorem 1.4: Powers of i

The powers of ii cycle with period 4:

i0=1,i1=i,i2=1,i3=i,i4=1,i^0 = 1, \quad i^1 = i, \quad i^2 = -1, \quad i^3 = -i, \quad i^4 = 1, \quad \ldots

In general, in=inmod4i^n = i^{n \mod 4}.

Example 1.5: Computing Powers of i

Compute i100i^{100} and i2023i^{2023}.

  • i100=i425=(i4)25=125=1i^{100} = i^{4 \cdot 25} = (i^4)^{25} = 1^{25} = 1
  • i2023=i4505+3=(i4)505i3=1(i)=ii^{2023} = i^{4 \cdot 505 + 3} = (i^4)^{505} \cdot i^3 = 1 \cdot (-i) = -i
Definition 1.4: ℂ as a Vector Space

C\mathbb{C} is a 2-dimensional vector space over R\mathbb{R} with basis {1,i}\{1, i\}. Every zCz \in \mathbb{C} can be written uniquely as:

z=a1+bi=a+bi(a,bR)z = a \cdot 1 + b \cdot i = a + bi \quad (a, b \in \mathbb{R})
Remark 1.3: ℂ as 1-dimensional over itself

As a vector space over itself, C\mathbb{C} is 1-dimensional. This distinction matters: dimR(C)=2\dim_{\mathbb{R}}(\mathbb{C}) = 2 but dimC(C)=1\dim_{\mathbb{C}}(\mathbb{C}) = 1.

2. Conjugate and Modulus

Definition 1.2: Complex Conjugate and Modulus

For z=a+biCz = a + bi \in \mathbb{C}:

  • The complex conjugate is zˉ=abi\bar{z} = a - bi
  • The modulus (or absolute value) is z=a2+b2|z| = \sqrt{a^2 + b^2}
  • The real part is Re(z)=a\text{Re}(z) = a
  • The imaginary part is Im(z)=b\text{Im}(z) = b
Theorem 1.2: Properties of Conjugation and Modulus

For all z,wCz, w \in \mathbb{C}:

  1. z+w=zˉ+wˉ\overline{z + w} = \bar{z} + \bar{w} and zw=zˉwˉ\overline{zw} = \bar{z} \cdot \bar{w}
  2. zzˉ=z2z \cdot \bar{z} = |z|^2
  3. zw=zw|zw| = |z| \cdot |w|
  4. z+zˉ=2Re(z)z + \bar{z} = 2\text{Re}(z) and zzˉ=2iIm(z)z - \bar{z} = 2i \cdot \text{Im}(z)
  5. zˉˉ=z\bar{\bar{z}} = z
  6. zR    zˉ=zz \in \mathbb{R} \iff \bar{z} = z
Proof of Theorem 1.2:

Property 2: Let z=a+biz = a + bi. Then:

zzˉ=(a+bi)(abi)=a2(bi)2=a2b2i2=a2+b2=z2z \cdot \bar{z} = (a + bi)(a - bi) = a^2 - (bi)^2 = a^2 - b^2i^2 = a^2 + b^2 = |z|^2

Property 3: Using Property 2:

zw2=(zw)(zw)=zwzˉwˉ=(zzˉ)(wwˉ)=z2w2|zw|^2 = (zw)(\overline{zw}) = zw \bar{z} \bar{w} = (z\bar{z})(w\bar{w}) = |z|^2 |w|^2

Taking square roots (all quantities are non-negative) gives zw=zw|zw| = |z||w|.

Example 1.1: Division Using Conjugates

To compute 2+3i12i\frac{2 + 3i}{1 - 2i}, multiply by 12i12i\frac{\overline{1-2i}}{\overline{1-2i}}:

2+3i12i=(2+3i)(1+2i)(12i)(1+2i)=2+4i+3i+6i21+4=2+7i65=4+7i5\frac{2 + 3i}{1 - 2i} = \frac{(2 + 3i)(1 + 2i)}{(1 - 2i)(1 + 2i)} = \frac{2 + 4i + 3i + 6i^2}{1 + 4} = \frac{2 + 7i - 6}{5} = \frac{-4 + 7i}{5}

So the answer is 45+75i\frac{-4}{5} + \frac{7}{5}i.

Example 1.2: Computing Modulus

Find 34i|3 - 4i| and 2+2i|2 + 2i|.

  • 34i=32+(4)2=9+16=25=5|3 - 4i| = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5
  • 2+2i=22+22=8=22|2 + 2i| = \sqrt{2^2 + 2^2} = \sqrt{8} = 2\sqrt{2}
Theorem 1.3: Conjugate of Real Polynomial Roots

If p(x)p(x) is a polynomial with real coefficients and z=a+biz = a + bi is a root, then zˉ=abi\bar{z} = a - bi is also a root.

Proof of Theorem 1.3:

Let p(z)=anzn++a1z+a0p(z) = a_n z^n + \cdots + a_1 z + a_0 with aiRa_i \in \mathbb{R}.

If p(z)=0p(z) = 0, then:

p(z)=anzn++a0=anzˉn++a0=p(zˉ)\overline{p(z)} = \overline{a_n z^n + \cdots + a_0} = a_n \bar{z}^n + \cdots + a_0 = p(\bar{z})

Since p(z)=0p(z) = 0, we have p(zˉ)=p(z)=0ˉ=0p(\bar{z}) = \overline{p(z)} = \bar{0} = 0.

Remark 1.2: Complex Roots Come in Pairs

This theorem explains why quadratics with real coefficients either have two real roots or two complex conjugate roots. For example, x2+1=0x^2 + 1 = 0 has roots ±i\pm i.

Definition 1.3: Multiplicative Inverse

For z=a+bi0z = a + bi \neq 0, the multiplicative inverse is:

z1=1z=zˉz2=abia2+b2z^{-1} = \frac{1}{z} = \frac{\bar{z}}{|z|^2} = \frac{a - bi}{a^2 + b^2}
Example 1.3: Finding Inverses

Find (3+4i)1(3 + 4i)^{-1}.

Solution:

(3+4i)1=34i32+42=34i25=325425i(3 + 4i)^{-1} = \frac{3 - 4i}{3^2 + 4^2} = \frac{3 - 4i}{25} = \frac{3}{25} - \frac{4}{25}i

Verify: (3+4i)(325425i)=9+1625+12+1225i=1(3 + 4i)(\frac{3}{25} - \frac{4}{25}i) = \frac{9 + 16}{25} + \frac{-12 + 12}{25}i = 1

3. Polar Form and Euler's Formula

The polar form reveals the geometric meaning of complex numbers and makes multiplication and powers much simpler.

Definition 1.3: Polar Form

Every non-zero complex number zz can be written as:

z=r(cosθ+isinθ)z = r(\cos\theta + i\sin\theta)

where:

  • r=zr = |z| is the modulus
  • θ=arg(z)\theta = \arg(z) is the argument (angle from positive real axis)
Theorem 1.3: Euler's Formula

For any θR\theta \in \mathbb{R}:

eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta

Thus every non-zero complex number can be written as z=reiθz = re^{i\theta}.

Remark 1.2: Multiplication in Polar Form

If z1=r1eiθ1z_1 = r_1 e^{i\theta_1} and z2=r2eiθ2z_2 = r_2 e^{i\theta_2}, then:

z1z2=r1r2ei(θ1+θ2)z_1 z_2 = r_1 r_2 e^{i(\theta_1 + \theta_2)}

Multiplication scales by the product of moduli and rotates by the sum of arguments.

Example 1.2: Polar Form Conversion

Convert z=1+iz = 1 + i to polar form.

  • Modulus: z=12+12=2|z| = \sqrt{1^2 + 1^2} = \sqrt{2}
  • Argument: θ=arctan(1/1)=π/4\theta = \arctan(1/1) = \pi/4

Thus z=2eiπ/4=2(cosπ4+isinπ4)z = \sqrt{2} e^{i\pi/4} = \sqrt{2}(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4}).

Example 1.3: Converting to Rectangular Form

Convert z=4eiπ/3z = 4e^{i\pi/3} to rectangular form.

Solution:

z=4(cosπ3+isinπ3)=4(12+i32)=2+23iz = 4(\cos\frac{\pi}{3} + i\sin\frac{\pi}{3}) = 4(\frac{1}{2} + i\frac{\sqrt{3}}{2}) = 2 + 2\sqrt{3}i
Definition 3.1: Principal Argument

The principal argument of zz, denoted Arg(z)\text{Arg}(z) (capital A), is the unique value of arg(z)\arg(z) in the interval (π,π](-\pi, \pi].

Example 3.1: Finding Arguments

Find the principal argument of:

  • z=1z = 1: Arg(1)=0\text{Arg}(1) = 0
  • z=iz = i: Arg(i)=π/2\text{Arg}(i) = \pi/2
  • z=1z = -1: Arg(1)=π\text{Arg}(-1) = \pi
  • z=iz = -i: Arg(i)=π/2\text{Arg}(-i) = -\pi/2
  • z=1iz = -1 - i: Arg(1i)=3π/4\text{Arg}(-1-i) = -3\pi/4
Theorem 3.1: Argument Properties

For nonzero complex numbers zz and ww:

  1. arg(zw)=arg(z)+arg(w)\arg(zw) = \arg(z) + \arg(w) (modulo 2π2\pi)
  2. arg(z/w)=arg(z)arg(w)\arg(z/w) = \arg(z) - \arg(w) (modulo 2π2\pi)
  3. arg(zˉ)=arg(z)\arg(\bar{z}) = -\arg(z)
  4. arg(zn)=narg(z)\arg(z^n) = n \cdot \arg(z) (modulo 2π2\pi)
Remark 3.1: Why Polar Form is Useful

Polar form makes multiplication simple: multiply moduli and add arguments. This is much easier than expanding (a+bi)(c+di)(a + bi)(c + di) in rectangular form, especially for powers and roots.

Example 3.2: Multiplication in Polar Form

Multiply z1=2eiπ/6z_1 = 2e^{i\pi/6} and z2=3eiπ/4z_2 = 3e^{i\pi/4}.

Solution:

z1z2=23ei(π/6+π/4)=6ei(2π+3π)/12=6ei5π/12z_1 z_2 = 2 \cdot 3 \cdot e^{i(\pi/6 + \pi/4)} = 6e^{i(2\pi + 3\pi)/12} = 6e^{i5\pi/12}
Example 3.3: Division in Polar Form

Divide z1=8eiπ/3z_1 = 8e^{i\pi/3} by z2=2eiπ/6z_2 = 2e^{i\pi/6}.

Solution:

z1z2=82ei(π/3π/6)=4eiπ/6=4(32+12i)=23+2i\frac{z_1}{z_2} = \frac{8}{2} e^{i(\pi/3 - \pi/6)} = 4e^{i\pi/6} = 4(\frac{\sqrt{3}}{2} + \frac{1}{2}i) = 2\sqrt{3} + 2i

4. De Moivre's Theorem and Roots of Unity

Theorem 1.4: De Moivre's Theorem

For any θR\theta \in \mathbb{R} and nZn \in \mathbb{Z}:

(cosθ+isinθ)n=cos(nθ)+isin(nθ)(\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta)

Equivalently, (eiθ)n=einθ(e^{i\theta})^n = e^{in\theta}.

Example 1.3: Computing Powers

Compute (1+i)10(1 + i)^{10}.

We have 1+i=2eiπ/41 + i = \sqrt{2} e^{i\pi/4}, so:

(1+i)10=(2)10e10iπ/4=32ei5π/2(1 + i)^{10} = (\sqrt{2})^{10} e^{10 \cdot i\pi/4} = 32 e^{i \cdot 5\pi/2}

Since ei5π/2=eiπ/2=ie^{i \cdot 5\pi/2} = e^{i\pi/2} = i, we get:

(1+i)10=32i(1 + i)^{10} = 32i
Definition 1.4: Roots of Unity

The nnth roots of unity are the solutions to zn=1z^n = 1. They are:

ωk=e2πik/n=cos2πkn+isin2πkn,k=0,1,,n1\omega_k = e^{2\pi i k / n} = \cos\frac{2\pi k}{n} + i\sin\frac{2\pi k}{n}, \quad k = 0, 1, \ldots, n-1

The primitive nnth root of unity is ω=e2πi/n\omega = e^{2\pi i / n}.

Theorem 1.5: nth Roots of Any Complex Number

If w=reiϕ0w = r e^{i\phi} \neq 0, then the nn solutions to zn=wz^n = w are:

zk=r1/nei(ϕ+2πk)/n,k=0,1,,n1z_k = r^{1/n} e^{i(\phi + 2\pi k)/n}, \quad k = 0, 1, \ldots, n-1
Example 1.4: Cube Roots of -8

Find all cube roots of 8-8.

Write 8=8eiπ-8 = 8 e^{i\pi}. The cube roots are:

zk=2ei(π+2πk)/3,k=0,1,2z_k = 2 e^{i(\pi + 2\pi k)/3}, \quad k = 0, 1, 2
  • k=0k = 0: z0=2eiπ/3=2(12+32i)=1+3iz_0 = 2e^{i\pi/3} = 2(\frac{1}{2} + \frac{\sqrt{3}}{2}i) = 1 + \sqrt{3}i
  • k=1k = 1: z1=2eiπ=2z_1 = 2e^{i\pi} = -2
  • k=2k = 2: z2=2ei5π/3=13iz_2 = 2e^{i5\pi/3} = 1 - \sqrt{3}i
Example 4.3: Computing (1 - i)^8

Compute (1i)8(1 - i)^8 using polar form.

Solution: First convert to polar:

1i=2,arg(1i)=π/4|1 - i| = \sqrt{2}, \quad \arg(1-i) = -\pi/4

So 1i=2eiπ/41 - i = \sqrt{2}e^{-i\pi/4}.

(1i)8=(2)8e8iπ/4=16e2πi=161=16(1 - i)^8 = (\sqrt{2})^8 e^{-8i\pi/4} = 16 e^{-2\pi i} = 16 \cdot 1 = 16
Theorem 4.2: Product of Roots of Unity

For n1n \geq 1, the product of all nnth roots of unity is:

k=0n1e2πik/n=(1)n+1\prod_{k=0}^{n-1} e^{2\pi ik/n} = (-1)^{n+1}
Proof:

Using properties of exponents:

k=0n1e2πik/n=e2πik=0n1k/n=e2πin(n1)/(2n)=eiπ(n1)\prod_{k=0}^{n-1} e^{2\pi ik/n} = e^{2\pi i \sum_{k=0}^{n-1} k/n} = e^{2\pi i \cdot n(n-1)/(2n)} = e^{i\pi(n-1)}

When n1n-1 is even, this equals 1. When n1n-1 is odd, this equals -1.

So the product is (1)n1=(1)n+1(-1)^{n-1} = (-1)^{n+1}.

Corollary 1.1: Sum of Roots of Unity

For n2n \geq 2:

k=0n1ωk=0where ω=e2πi/n\sum_{k=0}^{n-1} \omega^k = 0 \quad \text{where } \omega = e^{2\pi i/n}
Proof of Corollary 1.1:

This is a geometric series with ratio ω1\omega \neq 1:

k=0n1ωk=1ωn1ω=111ω=0\sum_{k=0}^{n-1} \omega^k = \frac{1 - \omega^n}{1 - \omega} = \frac{1 - 1}{1 - \omega} = 0
Example 4.1: 5th Roots of Unity

The 5th roots of unity are ωk=e2πik/5\omega_k = e^{2\pi ik/5} for k=0,1,2,3,4k = 0, 1, 2, 3, 4.

ω0=1,ω1=e2πi/5,ω2=e4πi/5,ω3=e6πi/5,ω4=e8πi/5\omega_0 = 1, \quad \omega_1 = e^{2\pi i/5}, \quad \omega_2 = e^{4\pi i/5}, \quad \omega_3 = e^{6\pi i/5}, \quad \omega_4 = e^{8\pi i/5}

These form a regular pentagon on the unit circle!

Theorem 4.1: Properties of Roots of Unity

Let ω=e2πi/n\omega = e^{2\pi i/n} be a primitive nnth root of unity.

  1. The nnth roots of unity are 1,ω,ω2,,ωn11, \omega, \omega^2, \ldots, \omega^{n-1}
  2. They form a cyclic group of order nn under multiplication
  3. They are evenly spaced on the unit circle
  4. ωn=1\omega^n = 1 and ωk1\omega^k \neq 1 for 0<k<n0 < k < n
  5. ωk=ωnk=ωk\overline{\omega^k} = \omega^{n-k} = \omega^{-k}
Example 4.2: Square Roots of i

Problem: Find all square roots of ii.

Solution: Write i=eiπ/2i = e^{i\pi/2}.

zk=ei(π/2+2πk)/2=eiπ(1+4k)/4,k=0,1z_k = e^{i(\pi/2 + 2\pi k)/2} = e^{i\pi(1 + 4k)/4}, \quad k = 0, 1
  • k=0k = 0: z0=eiπ/4=12(1+i)z_0 = e^{i\pi/4} = \frac{1}{\sqrt{2}}(1 + i)
  • k=1k = 1: z1=ei5π/4=12(1i)z_1 = e^{i5\pi/4} = \frac{1}{\sqrt{2}}(-1 - i)

Verify: (1+i2)2=1+2i12=i\left(\frac{1+i}{\sqrt{2}}\right)^2 = \frac{1 + 2i - 1}{2} = i

Remark 4.1: Applications of Roots of Unity

Roots of unity appear in:

  • Discrete Fourier Transform: Uses nnth roots of unity
  • Cyclotomic polynomials: Minimal polynomials of primitive roots
  • Filter design: Poles/zeros on the unit circle
  • Group theory: Cyclic groups of finite order

5. The Fundamental Theorem of Algebra

Theorem 1.6: Fundamental Theorem of Algebra

Every non-constant polynomial with complex coefficients has at least one root in C\mathbb{C}.

Equivalently, C\mathbb{C} is algebraically closed.

Remark 1.3: Importance for Linear Algebra

This theorem guarantees that the characteristic polynomial of any matrix over C\mathbb{C} factors completely into linear factors. Hence:

  • Every complex matrix has at least one eigenvalue
  • Every complex matrix can be put into Jordan normal form
  • The spectral theorem has its cleanest statement over C\mathbb{C}
Corollary 1.2: Complete Factorization

Every polynomial p(z)=anzn++a1z+a0p(z) = a_n z^n + \cdots + a_1 z + a_0 with an0a_n \neq 0 can be written as:

p(z)=an(zr1)(zr2)(zrn)p(z) = a_n(z - r_1)(z - r_2) \cdots (z - r_n)

where r1,,rnCr_1, \ldots, r_n \in \mathbb{C} are the roots (counting multiplicity).

Example 5.1: Factoring Over ℂ

Factor p(x)=x4+4p(x) = x^4 + 4 over C\mathbb{C}.

Solution: Find roots by solving x4=4=4eiπx^4 = -4 = 4e^{i\pi}:

xk=2ei(π+2πk)/4,k=0,1,2,3x_k = \sqrt{2} e^{i(\pi + 2\pi k)/4}, \quad k = 0, 1, 2, 3

The roots are:

  • x0=2eiπ/4=1+ix_0 = \sqrt{2} e^{i\pi/4} = 1 + i
  • x1=2ei3π/4=1+ix_1 = \sqrt{2} e^{i3\pi/4} = -1 + i
  • x2=2ei5π/4=1ix_2 = \sqrt{2} e^{i5\pi/4} = -1 - i
  • x3=2ei7π/4=1ix_3 = \sqrt{2} e^{i7\pi/4} = 1 - i
x4+4=(x1i)(x+1i)(x+1+i)(x1+i)x^4 + 4 = (x - 1 - i)(x + 1 - i)(x + 1 + i)(x - 1 + i)
Theorem 5.1: Real Polynomials Factor into Linear and Quadratic Factors

Every polynomial with real coefficients factors over R\mathbb{R}into a product of linear factors and irreducible quadratic factors.

Proof:

By the Fundamental Theorem, p(x)p(x) factors completely over C\mathbb{C}. Since coefficients are real, complex roots come in conjugate pairs: if rr is a root, so is rˉ\bar{r}.

Each conjugate pair gives a real quadratic factor:

(xr)(xrˉ)=x2(r+rˉ)x+rrˉ=x22Re(r)x+r2(x - r)(x - \bar{r}) = x^2 - (r + \bar{r})x + r\bar{r} = x^2 - 2\text{Re}(r)x + |r|^2

This is a quadratic with real coefficients and negative discriminant (irreducible over R\mathbb{R}).

Example 5.2: Factoring Over ℝ

Factor x4+4x^4 + 4 over R\mathbb{R}.

Solution: Pair conjugate roots:

(x(1+i))(x(1i))=x22x+2(x - (1+i))(x - (1-i)) = x^2 - 2x + 2
(x(1+i))(x(1i))=x2+2x+2(x - (-1+i))(x - (-1-i)) = x^2 + 2x + 2

Therefore:

x4+4=(x22x+2)(x2+2x+2)x^4 + 4 = (x^2 - 2x + 2)(x^2 + 2x + 2)

6. Geometric Interpretation

Complex numbers have a beautiful geometric interpretation as points (or vectors) in the Euclidean plane, often called the complex plane or Argand diagram.

Definition 6.1: The Complex Plane

The complex plane identifies z=a+biz = a + bi with the point (a,b)R2(a, b) \in \mathbb{R}^2.

  • The real axis is the horizontal axis (where b=0b = 0)
  • The imaginary axis is the vertical axis (where a=0a = 0)
  • The modulus z|z| is the distance from the origin
  • The argument arg(z)\arg(z) is the angle from the positive real axis
Theorem 6.1: Geometric Meaning of Operations
  • Addition: z+wz + w corresponds to vector addition (parallelogram law)
  • Multiplication by eiθe^{i\theta}: Rotates by angle θ\theta counterclockwise
  • Multiplication by rr: Scales by factor rr
  • Conjugation: Reflects across the real axis
  • Inversion 1/z1/z: Inverts modulus and negates argument
Example 6.1: Rotation by 90°

Multiplying by ii rotates by 90°90°:

i(a+bi)=ai+bi2=b+aii \cdot (a + bi) = ai + bi^2 = -b + ai

The point (a,b)(a, b) becomes (b,a)(-b, a)—exactly a 90°90° counterclockwise rotation!

Theorem 6.2: Triangle Inequality

For all z,wCz, w \in \mathbb{C}:

z+wz+w|z + w| \leq |z| + |w|

Equality holds if and only if zz and ww have the same argument (point in the same direction from the origin).

Proof of Theorem 6.2:

We compute z+w2|z + w|^2:

z+w2=(z+w)(zˉ+wˉ)=z2+zwˉ+zˉw+w2|z + w|^2 = (z + w)(\bar{z} + \bar{w}) = |z|^2 + z\bar{w} + \bar{z}w + |w|^2

Note that zwˉ+zˉw=2Re(zwˉ)2zwˉ=2zwz\bar{w} + \bar{z}w = 2\text{Re}(z\bar{w}) \leq 2|z\bar{w}| = 2|z||w|.

z+w2z2+2zw+w2=(z+w)2|z + w|^2 \leq |z|^2 + 2|z||w| + |w|^2 = (|z| + |w|)^2

Taking square roots gives the triangle inequality.

Corollary 6.1: Reverse Triangle Inequality

For all z,wCz, w \in \mathbb{C}:

zwzw\big||z| - |w|\big| \leq |z - w|
Example 6.2: Circles in the Complex Plane

The equation zz0=r|z - z_0| = r describes a circle:

  • Center: z0z_0
  • Radius: rr

For example, z2i=3|z - 2 - i| = 3 is a circle centered at 2+i2 + i with radius 3.

Example 6.3: Lines in the Complex Plane

The equation Re(aˉz)=c\text{Re}(\bar{a}z) = c describes a line.

For a=1+ia = 1 + i and c=2c = 2:

Re((1i)(x+iy))=Re(x+y+i(yx))=x+y=2\text{Re}((1-i)(x+iy)) = \text{Re}(x + y + i(y - x)) = x + y = 2

This is the line x+y=2x + y = 2.

Definition 6.2: Unit Circle

The unit circle is the set {zC:z=1}\{z \in \mathbb{C} : |z| = 1\}. Points on the unit circle have the form eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta.

Remark 6.1: Complex Numbers and 2D Geometry

Complex numbers elegantly encode 2D geometry:

  • Distance between zz and ww: zw|z - w|
  • Midpoint of zz and ww: z+w2\frac{z + w}{2}
  • Rotation by θ\theta: multiply by eiθe^{i\theta}
  • Reflection across real axis: take conjugate
Example 6.4: Rotation of a Point

Rotate the point z=3+4iz = 3 + 4i by 90°90° counterclockwise around the origin.

Solution:

z=eiπ/2z=i(3+4i)=3i+4i2=4+3iz' = e^{i\pi/2} \cdot z = i(3 + 4i) = 3i + 4i^2 = -4 + 3i

The point (3,4)(3, 4) becomes (4,3)(-4, 3).

7. Connection to Linear Algebra

Complex numbers are deeply connected to linear algebra in several ways.

  • Eigenvalues: Even real matrices may have complex eigenvalues. For example, rotation matrices have eigenvalues e±iθe^{\pm i\theta}.
  • Characteristic polynomial: Factors completely over C\mathbb{C}, guaranteeing eigenvalues exist.
  • Spectral theorem: Normal matrices are unitarily diagonalizable over C\mathbb{C}.
  • Jordan form: Every matrix has a Jordan normal form over C\mathbb{C}.
  • Inner products: Complex inner products use conjugation: u,v=uˉivi\langle u, v \rangle = \sum \bar{u}_i v_i.
Example 7.1: Rotation Matrix Eigenvalues

The 2D rotation matrix by angle θ\theta:

Rθ=(cosθsinθsinθcosθ)R_\theta = \begin{pmatrix} \cos\theta & -\sin\theta \\ \sin\theta & \cos\theta \end{pmatrix}

has characteristic polynomial λ22cosθλ+1\lambda^2 - 2\cos\theta \cdot \lambda + 1.

The eigenvalues are λ=cosθ±isinθ=e±iθ\lambda = \cos\theta \pm i\sin\theta = e^{\pm i\theta}.

For θ0,π\theta \neq 0, \pi, these are complex (non-real) eigenvalues!

Example 7.2: Complex Inner Product

For vectors u,vCnu, v \in \mathbb{C}^n, the standard inner product is:

u,v=k=1nuˉkvk=uˉTv\langle u, v \rangle = \sum_{k=1}^n \bar{u}_k v_k = \bar{u}^T v

Note the conjugation on the first argument! This ensures u,u0\langle u, u \rangle \geq 0.

Remark 7.1: Why Conjugation in Inner Products?

Without conjugation, iu,iu=i2u2=u2<0\langle iu, iu \rangle = i^2 \|u\|^2 = -\|u\|^2 < 0.

With conjugation, iu,iu=iˉiu2=i2u2=u2>0\langle iu, iu \rangle = \bar{i} \cdot i \|u\|^2 = |i|^2 \|u\|^2 = \|u\|^2 > 0. ✓

Example 7.3: Hermitian Matrices

A matrix AA is Hermitian if A=AA^* = A (conjugate transpose equals itself).

A=(23i3+i5)A = \begin{pmatrix} 2 & 3-i \\ 3+i & 5 \end{pmatrix}

Hermitian matrices have:

  • Real eigenvalues (even over C\mathbb{C})
  • Orthogonal eigenvectors
  • Unitary diagonalization: A=UDUA = UDU^*
Theorem 7.1: Complex Eigenvalues of Real Matrices

If AA is a real matrix and λC\lambda \in \mathbb{C} is an eigenvalue with eigenvector vv, then λˉ\bar{\lambda} is also an eigenvalue with eigenvector vˉ\bar{v}.

Proof:

Since Av=λvAv = \lambda v and AA has real entries (Aˉ=A\bar{A} = A):

Avˉ=Aˉvˉ=Av=λv=λˉvˉA\bar{v} = \bar{A}\bar{v} = \overline{Av} = \overline{\lambda v} = \bar{\lambda}\bar{v}

8. Worked Examples

Example 8.1: Complex Division

Problem: Compute 3+4i1+2i\frac{3 + 4i}{1 + 2i}.

Solution: Multiply by conjugate:

3+4i1+2i12i12i=(3+4i)(12i)1+4=36i+4i8i25\frac{3 + 4i}{1 + 2i} \cdot \frac{1 - 2i}{1 - 2i} = \frac{(3 + 4i)(1 - 2i)}{1 + 4} = \frac{3 - 6i + 4i - 8i^2}{5}
=32i+85=112i5=11525i= \frac{3 - 2i + 8}{5} = \frac{11 - 2i}{5} = \frac{11}{5} - \frac{2}{5}i
Example 8.2: Finding All Roots

Problem: Find all solutions to z4=16z^4 = -16.

Solution: Write 16=16eiπ-16 = 16e^{i\pi}.

zk=2ei(π+2πk)/4=2eiπ(1+2k)/4,k=0,1,2,3z_k = 2e^{i(\pi + 2\pi k)/4} = 2e^{i\pi(1 + 2k)/4}, \quad k = 0, 1, 2, 3
  • k=0k=0: z0=2eiπ/4=2(1+i)z_0 = 2e^{i\pi/4} = \sqrt{2}(1 + i)
  • k=1k=1: z1=2ei3π/4=2(1+i)z_1 = 2e^{i3\pi/4} = \sqrt{2}(-1 + i)
  • k=2k=2: z2=2ei5π/4=2(1i)z_2 = 2e^{i5\pi/4} = \sqrt{2}(-1 - i)
  • k=3k=3: z3=2ei7π/4=2(1i)z_3 = 2e^{i7\pi/4} = \sqrt{2}(1 - i)
Example 8.3: Proving Trigonometric Identities

Problem: Prove cos(2θ)=cos2θsin2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta.

Solution: Use De Moivre:

cos(2θ)+isin(2θ)=(cosθ+isinθ)2\cos(2\theta) + i\sin(2\theta) = (\cos\theta + i\sin\theta)^2
=cos2θ+2icosθsinθ+i2sin2θ= \cos^2\theta + 2i\cos\theta\sin\theta + i^2\sin^2\theta
=(cos2θsin2θ)+i(2cosθsinθ)= (\cos^2\theta - \sin^2\theta) + i(2\cos\theta\sin\theta)

Comparing real parts: cos(2θ)=cos2θsin2θ\cos(2\theta) = \cos^2\theta - \sin^2\theta.

Example 8.4: Powers via Polar Form

Problem: Compute (3+i)6(\sqrt{3} + i)^6.

Solution: Convert to polar form:

3+i=3+1=2,arg(3+i)=arctan(1/3)=π/6|\sqrt{3} + i| = \sqrt{3 + 1} = 2, \quad \arg(\sqrt{3} + i) = \arctan(1/\sqrt{3}) = \pi/6

So 3+i=2eiπ/6\sqrt{3} + i = 2e^{i\pi/6}.

(3+i)6=26ei6π/6=64eiπ=64(1)=64(\sqrt{3} + i)^6 = 2^6 e^{i \cdot 6 \cdot \pi/6} = 64 e^{i\pi} = 64(-1) = -64
Example 8.5: Solving Quadratics

Problem: Solve z2+2z+5=0z^2 + 2z + 5 = 0.

Solution: Use the quadratic formula:

z=2±4202=2±162=2±4i2=1±2iz = \frac{-2 \pm \sqrt{4 - 20}}{2} = \frac{-2 \pm \sqrt{-16}}{2} = \frac{-2 \pm 4i}{2} = -1 \pm 2i
Example 8.6: Verifying Euler's Formula

Problem: Verify eiπ+1=0e^{i\pi} + 1 = 0.

Solution:

eiπ=cosπ+isinπ=1+i0=1e^{i\pi} = \cos\pi + i\sin\pi = -1 + i \cdot 0 = -1

Therefore eiπ+1=1+1=0e^{i\pi} + 1 = -1 + 1 = 0. ✓

Example 8.7: Product of Complex Numbers

Problem: Compute (1+i)(23i)(1+2i)(1 + i)(2 - 3i)(1 + 2i).

Solution: First multiply (1+i)(23i)(1 + i)(2 - 3i):

(1+i)(23i)=23i+2i3i2=2i+3=5i(1 + i)(2 - 3i) = 2 - 3i + 2i - 3i^2 = 2 - i + 3 = 5 - i

Then multiply by (1+2i)(1 + 2i):

(5i)(1+2i)=5+10ii2i2=5+9i+2=7+9i(5 - i)(1 + 2i) = 5 + 10i - i - 2i^2 = 5 + 9i + 2 = 7 + 9i
Example 8.8: Complex Exponential

Problem: Simplify e2+iπ/4e^{2 + i\pi/4}.

Solution:

e2+iπ/4=e2eiπ/4=e2(cosπ4+isinπ4)=e222(1+i)e^{2 + i\pi/4} = e^2 \cdot e^{i\pi/4} = e^2(\cos\frac{\pi}{4} + i\sin\frac{\pi}{4}) = e^2 \cdot \frac{\sqrt{2}}{2}(1 + i)
=e222(1+i)5.22(1+i)= \frac{e^2\sqrt{2}}{2}(1 + i) \approx 5.22(1 + i)
Example 8.9: Using De Moivre for Trig

Problem: Express cos(3θ)\cos(3\theta) in terms of cosθ\cos\theta.

Solution: Let c=cosθc = \cos\theta and s=sinθs = \sin\theta.

cos(3θ)+isin(3θ)=(c+is)3\cos(3\theta) + i\sin(3\theta) = (c + is)^3
=c3+3c2(is)+3c(is)2+(is)3=c3+3c2is3cs2is3= c^3 + 3c^2(is) + 3c(is)^2 + (is)^3 = c^3 + 3c^2 is - 3cs^2 - is^3
=(c33cs2)+i(3c2ss3)= (c^3 - 3cs^2) + i(3c^2s - s^3)

Taking real parts: cos(3θ)=c33c(1c2)=4c33c=4cos3θ3cosθ\cos(3\theta) = c^3 - 3c(1-c^2) = 4c^3 - 3c = 4\cos^3\theta - 3\cos\theta.

Example 8.10: Absolute Value Inequality

Problem: Show that z1+z22+z1z22=2(z12+z22)|z_1 + z_2|^2 + |z_1 - z_2|^2 = 2(|z_1|^2 + |z_2|^2).

Solution: Expand using w2=wwˉ|w|^2 = w\bar{w}:

z1+z22=(z1+z2)(zˉ1+zˉ2)=z12+z1zˉ2+zˉ1z2+z22|z_1 + z_2|^2 = (z_1 + z_2)(\bar{z}_1 + \bar{z}_2) = |z_1|^2 + z_1\bar{z}_2 + \bar{z}_1 z_2 + |z_2|^2
z1z22=(z1z2)(zˉ1zˉ2)=z12z1zˉ2zˉ1z2+z22|z_1 - z_2|^2 = (z_1 - z_2)(\bar{z}_1 - \bar{z}_2) = |z_1|^2 - z_1\bar{z}_2 - \bar{z}_1 z_2 + |z_2|^2

Adding: z1+z22+z1z22=2z12+2z22|z_1 + z_2|^2 + |z_1 - z_2|^2 = 2|z_1|^2 + 2|z_2|^2. ✓

(This is the parallelogram law.)

9. Common Mistakes

Mistake 1: Forgetting conjugation in modulus

z2=zzˉ|z|^2 = z \cdot \bar{z}, NOT zz=z2z \cdot z = z^2. For example, i2=i(i)=1|i|^2 = i \cdot (-i) = 1, but i2=1i^2 = -1.

Mistake 2: Wrong argument quadrant

arctan(b/a)\arctan(b/a) doesn't account for the quadrant. For 1+i-1 + i, arctan(1)=π/4\arctan(-1) = -\pi/4, but the correct argument is 3π/43\pi/4.

Mistake 3: Missing roots

When finding nnth roots, there are always nn distinct roots. Don't forget to find all of them using e2πik/ne^{2\pi ik/n} for k=0,1,,n1k = 0, 1, \ldots, n-1.

Mistake 4: Treating i as a variable

ii is a constant with i2=1i^2 = -1. Don't treat it like an unknown. Simplify powers of ii: i1=i,i2=1,i3=i,i4=1i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1, then repeat.

Mistake 5: Trying to order complex numbers

You cannot say 1+i>21 + i > 2 or i>0i > 0. Complex numbers have no compatible ordering. Only compare magnitudes: 1+i=2<2|1 + i| = \sqrt{2} < 2.

10. Key Takeaways

Construction

C=R2\mathbb{C} = \mathbb{R}^2 with multiplication (a,b)(c,d)=(acbd,ad+bc)(a,b)(c,d) = (ac-bd, ad+bc). This makes i2=1i^2 = -1.

Polar Form

z=reiθz = re^{i\theta} where r=zr = |z| and θ=arg(z)\theta = \arg(z). Multiplication scales and rotates.

Euler's Formula

eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta. The bridge between exponentials and trigonometry.

Algebraically Closed

Every polynomial over C\mathbb{C} factors completely. Every degree-nn polynomial has exactly nn roots.

Complex Numbers Practice
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1
What is the modulus of z=3+4iz = 3 + 4i?
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2
What is i2023i^{2023}?
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3
Express eiπ/3e^{i\pi/3} in rectangular form.
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4
What is (2+3i)(1i)\overline{(2 + 3i)(1 - i)}?
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5
How many cube roots does 8-8 have in C\mathbb{C}?
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6
If z=2|z| = 2 and arg(z)=π/4\arg(z) = \pi/4, what is z4z^4?
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7
Which statement about C\mathbb{C} is FALSE?
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8
What is k=0n1e2πik/n\sum_{k=0}^{n-1} e^{2\pi i k/n} for n2n \geq 2?
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9
What is Re(eiθ)\text{Re}(e^{i\theta})?
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10
If z=2eiπ/6z = 2e^{i\pi/6}, what is zˉ\bar{z}?
Medium
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The 4th roots of unity are:
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What is the principal argument of z=1iz = -1 - i?
Hard
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Frequently Asked Questions

Why do we need complex numbers in linear algebra?

Complex numbers are essential for spectral theory. Over ℝ, not all matrices have eigenvalues (e.g., rotation matrices). Over ℂ, the Fundamental Theorem of Algebra guarantees that every polynomial factors completely, so every matrix has eigenvalues.

What's the geometric meaning of complex multiplication?

Multiplying by z = re^{iθ} scales by r and rotates by θ. This makes complex numbers perfect for describing rotations and scaling in 2D, which generalizes to understanding linear operators geometrically.

Is there a 3D analog of complex numbers?

No in a strict sense—you can't extend ℂ to 3D while preserving all field properties. However, quaternions (4D) extend complex numbers and are useful for 3D rotations. Octonions extend further but lose associativity.

What does 'algebraically closed' mean precisely?

A field F is algebraically closed if every non-constant polynomial with coefficients in F has a root in F. Equivalently, every polynomial of degree n over F has exactly n roots (counting multiplicity) in F.

How do complex conjugates help with division?

To divide by z = a + bi, multiply numerator and denominator by z̄ = a - bi. This gives z·z̄ = |z|² in the denominator, which is a real number, making the division straightforward.

What is the triangle inequality for complex numbers?

For complex numbers z and w: |z + w| ≤ |z| + |w|. Geometrically, this says the length of one side of a triangle is at most the sum of the other two sides. Equality holds iff z and w point in the same direction.

Why is e^{iπ} = -1 called 'the most beautiful equation'?

Euler's identity e^{iπ} + 1 = 0 connects five fundamental constants: e, i, π, 1, and 0, using three basic operations: addition, multiplication, and exponentiation. It links analysis, algebra, and geometry in one elegant formula.

Can complex numbers be compared with < or >?

No! ℂ cannot be ordered compatibly with its field structure. If we tried to say i > 0, then i² = -1 > 0, which contradicts -1 < 0. Complex numbers have no natural ordering, only magnitude comparisons via |z|.

What's the difference between argument and principal argument?

The argument of z is any angle θ such that z = |z|e^{iθ}. Since e^{iθ} = e^{i(θ+2πk)}, the argument is only defined up to multiples of 2π. The principal argument restricts θ to a specific range, usually (-π, π] or [0, 2π).

How are complex numbers used in physics?

Complex numbers appear throughout physics: AC circuit analysis uses impedance (complex resistance), quantum mechanics uses complex wave functions, and signal processing uses Fourier transforms with complex exponentials.