Before starting this course, you should be familiar with:
Lp spaces and duality theory
For , the space consists of all measurable functions such that:
The space consists of functions with:
Functions that are equal almost everywhere are identified.
Two numbers and with are called conjugate exponents if:
We also say and are conjugate pairs.
Let and be conjugate exponents with . If and , then and:
Equality holds if and only if and are proportional almost everywhere.
Proof:
For , the result is immediate. For , use Young's inequality:
Apply this to and , then integrate. ∎
For and :
This is the triangle inequality for Lp spaces.
Proof:
For or , the result is straightforward.
For , write and apply Hölder's inequality to each term, then use that . ∎
For , the space is complete, i.e., it is a Banach space.
Proof:
Let be a Cauchy sequence in . Extract a subsequence such that .
Define . By Minkowski, , so the series converges a.e.
The limit exists a.e. and is in . The full sequence converges to by the Cauchy property. ∎
Let and let be the conjugate exponent. Then every bounded linear functional on is of the form:
for a unique . Moreover, .
Proof:
For finite measure spaces, define a set function . Show that and apply Radon-Nikodym to get .
Extend to σ-finite spaces by taking limits. The isometry follows from Hölder's inequality. ∎
Problem: Compute where on .
Solution:
We have .
This converges if and only if , i.e., .
For , .
For , .
The space is a Hilbert space with inner product:
The norm is induced by this inner product: .
For , the space is complete with respect to the norm.
That is, every Cauchy sequence in converges to a function in .
Proof:
Let be a Cauchy sequence in . Extract a subsequence such that .
Define . By Minkowski's inequality,
so . This implies the series converges almost everywhere, so exists a.e.
By Fatou's lemma, , which tends to 0 as by the Cauchy property. ∎
Let and be the conjugate exponent. Every bounded linear functional has the form
for a unique , with .
Proof:
Step 1: For a finite measure space, define for measurable sets .
Step 2: Show that is a signed measure with (using the boundedness of ).
Step 3: Apply the Radon-Nikodym theorem to get such that .
Step 4: Show that by testing on functions of the form .
Step 5: Extend to simple functions, then to all of by density.
Step 6: The isometry follows from Hölder's inequality and the choice of test functions. ∎
Problem: Compute where on for .
Solution:
We have .
This integral converges if and only if , i.e., or .
For ,
Therefore, .
For , .
Problem: Show that the functions on form an orthonormal set in .
Solution:
For ,
For ,
Therefore, is an orthonormal set. This is the basis for Fourier series theory.
Problem: Given where is the conjugate of , show that defines a bounded linear functional on .
Solution:
By Hölder's inequality,
so is bounded with .
To show equality, take . Then and , so .
This shows that every gives rise to a bounded linear functional on .
Problem: Show that if in and pointwise a.e., then a.e.
Solution:
Since in , there is a subsequence such that pointwise a.e.
But we also have pointwise a.e., so pointwise a.e.
Therefore, almost everywhere.
This demonstrates that Lp limits are unique up to almost everywhere equality, which is a consequence of completeness.
For , the dual space is isometrically isomorphic to where .
This means:
The Riesz representation theorem is one of the most important results in functional analysis:
The theorem was proved by Frigyes Riesz in 1907 for (the Hilbert space case) and later extended to general .
Lp spaces and duality are fundamental in PDE theory:
These applications show why Lp spaces are central to modern analysis and PDE theory.
Problem: Use Hölder's inequality to show that if and where , then and .
Solution:
This is exactly Hölder's inequality. For , this becomes the Cauchy-Schwarz inequality:
Hölder's inequality is one of the most important inequalities in analysis, used constantly in estimates.
Problem: On a finite measure space, show that for .
Solution:
For , use Hölder's inequality with exponents and :
Since the measure space is finite, , so .
This shows that on finite measure spaces, higher Lp spaces are contained in lower ones, the opposite of what happens on infinite measure spaces.
Problem: Given where is the conjugate of , show that defines a bounded linear functional on with norm .
Solution:
By Hölder's inequality, , so .
To show equality, take . Then and , so .
This shows that every gives rise to a bounded linear functional on , and the Riesz representation theorem shows that all functionals arise this way.
For and , we have:
These inequalities are used to prove that Lp spaces are uniformly convex for .
Proof:
The proof uses the convexity of the function for .
For , there are similar but more complicated inequalities. These results are fundamental in the geometry of Banach spaces. ∎
For , the space is uniformly convex: for any , there exists such that if and , then .
This property is crucial for the geometry of Lp spaces and has important consequences for optimization and fixed point theory.
The cases and are special:
These special cases require different techniques and have different properties than Lp for .
Interpolation theory studies how properties of operators on Lp spaces vary with :
Interpolation theory is a powerful tool that allows us to prove results for all Lp spaces by checking only a few values of .
Problem: Compute where on for and determine for which the function is in .
Solution:
We have .
This converges if and only if , i.e., or .
For ,
For , .
This shows that membership in Lp depends on both the function and the value of .
Problem: Show that Hölder's inequality is sharp by finding functions that achieve equality.
Solution:
Equality in Hölder's inequality holds when and are proportional almost everywhere.
For example, on , take and . Then
This shows that Hölder's inequality is optimal: the constant 1 cannot be improved.
Problem: Show that the functions form an orthogonal set in .
Solution:
Using trigonometric identities, we can show that:
This orthogonality is the foundation of Fourier series theory.
For and the conjugate exponent, the map where is an isometric isomorphism from onto .
This means that every bounded linear functional on comes from a unique element of , and the norms are equal.
Proof:
The Riesz representation theorem (Theorem 9.4) shows that the map is surjective.
Uniqueness follows from the fact that if for all , then a.e.
The isometry property was shown in Example 9.6. ∎
For , the space is reflexive: .
This follows from the duality and (since is the conjugate of and vice versa).
Lp spaces are central to Fourier analysis:
These connections make Lp spaces essential for harmonic analysis and signal processing.
The geometry of Lp spaces varies with :
Understanding the geometry of Lp spaces is crucial for many applications in analysis and optimization.
Key takeaways:
An Lp space (for 1 ≤ p ≤ ∞) consists of measurable functions f such that $\int |f|^p < \infty$ (or $\|f\|_\infty < \infty$ for p = ∞), modulo functions that are zero almost everywhere. It's a complete normed vector space (Banach space).
Hölder's inequality states that if $f \in L^p$ and $g \in L^q$ where $\frac{1}{p} + \frac{1}{q} = 1$, then $\|fg\|_1 \leq \|f\|_p \|g\|_q$. It's a generalization of the Cauchy-Schwarz inequality (which is the case p = q = 2).
Minkowski's inequality is the triangle inequality for Lp spaces: $\|f + g\|_p \leq \|f\|_p + \|g\|_p$. It ensures that the Lp norm satisfies the triangle inequality, making Lp a normed space.
L2 is a Hilbert space, meaning it has an inner product $\langle f, g \rangle = \int fg$ that induces the norm. This makes it particularly nice for analysis, as we can use geometric intuition and have concepts like orthogonality.
For 1 < p < ∞, the dual space (space of bounded linear functionals) of Lp is isometrically isomorphic to Lq where $\frac{1}{p} + \frac{1}{q} = 1$. This is the Riesz representation theorem. For p = 1, the dual is L∞, but the converse is more complicated.
Completeness means that every Cauchy sequence in Lp converges to a function in Lp. This is the Riesz-Fischer theorem and is crucial for many applications, as it ensures that limits of Lp functions remain in Lp.
On sets of finite measure, we have $L^q \subset L^p$ when p < q. On the whole real line, there's no general inclusion, but L1 ∩ L∞ is contained in all Lp. The Lp norms are related through interpolation theory.