MathIsimple

Analytic Geometry – Problem 31: Find the equations of its asymptotes

Question

A hyperbola is centered at the origin with transverse axis along the xx-axis. Its real axis length is 44 and its eccentricity is e=54e=\dfrac54.

Find the equations of its asymptotes.

Step-by-step solution

(1) The real axis length is 2a=4a=22a=4\Rightarrow a=2.

(2) Eccentricity e=ca=54c=ae=254=52e=\dfrac{c}{a}=\dfrac54\Rightarrow c=ae=2\cdot\frac54=\frac52.

(3) For a hyperbola x2a2y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1, we have c2=a2+b2c^2=a^2+b^2. Thus b2=c2a2=(52)222=2544=94,b=32.b^2=c^2-a^2=\left(\frac52\right)^2-2^2=\frac{25}{4}-4=\frac94,\quad b=\frac32. (4) The asymptotes are y=±bax=±3/22x=±34x.y=\pm\frac{b}{a}x=\pm\frac{3/2}{2}x=\pm\frac34x.

Final answer

The asymptotes are y=±34xy=\pm\dfrac34x.

Marking scheme

Step 1 — Setup

Checkpoint: identify a=2a=2 from the real axis length and set c=aec=ae (2 pts)

Step 2 — Key Calculation

Checkpoint: compute b2=c2a2=94b^2=c^2-a^2=\frac94 and use asymptote slope ±ba\pm\frac{b}{a} (3 pts)

Step 3 — Final Answer

Checkpoint: state y=±34xy=\pm\frac34x (2 pts)

Zero credit if: uses ellipse relation c2=a2b2c^2=a^2-b^2 for a hyperbola.

Deductions: -1 pt for arithmetic error in bb.

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