Question
Let be a filtration (an increasing sequence of -fields). Let be a stopping time with respect to , and let be an integer-valued random variable that is -measurable with Prove that is also a stopping time with respect to .
Step-by-step solution
Proof: Step 1. First decompose according to the values of :
Since , when , the condition implies , so holds automatically. Thus .
Step 2. Since , taking :
Moreover, since and , we have
Therefore
Step 3. In summary, for every , , so is a stopping time. QED.
Final answer
QED.
Marking scheme
The following is the complete marking scheme for this probability theory problem.
1. Checkpoints (max 7 pts total)
Core idea: Use the definition of to decompose and convert it into events in .
*The following steps form a single logical chain; points are awarded cumulatively:*
- Event decomposition [additive] (1 pt)
- Decompose the event by the values of , writing a union of the form:
- *Note: The upper limit of summation may be or (as long as subsequent handling is correct). If the union formula is not explicitly written but each term for each is correctly discussed subsequently, credit may still be awarded.*
- Applying the -measurability definition [additive] (3 pts)
- Identifying the measurable set (1 pt): State that (as the preimage of a Borel set under the random variable ) belongs to .
- Applying the definition (2 pts): Using the definition for all , conclude:
- *Scoring note: This is the most critical technical step. If the student only vaguely writes "since it is measurable, it belongs to " without explicitly invoking the structural definition of , deduct 1 point.*
- Monotonicity of the filtration and index restriction [additive] (2 pts)
- Index control (1 pt): State that since , when occurs we necessarily have (i.e., ), or state that when the intersection is the empty set (which belongs to ).
- Subset property (1 pt): Use to argue that the above non-empty intersections belong to .
- Conclusion [additive] (1 pt)
- State that -algebras are closed under finite unions, therefore , hence is a stopping time.
- *Note: This must be based on the preceding proof; stating only the conclusion without justification receives no credit.*
Total (max 7)
2. Zero-credit items
- Merely copying the problem conditions (e.g., listing "", " is -measurable").
- Merely listing the general definition of stopping time or -algebra without applying it to the specific variables and .
- Citing a theorem: Directly citing "if and is -measurable then is a stopping time" as a known result without providing a proof.
- Circular reasoning: Using the conclusion " is a stopping time" within the proof (e.g., using properties of ).
3. Deductions
*Only deduct for the most significant single error; deductions should not reduce the total below 0.*
- Index logic error (flat -2):
- Summing over up to in the decomposition and claiming for all (ignoring the case ).
- *Exception: If the student correctly identifies that the set is empty when , no deduction applies.*
- Symbol confusion or unclear definitions (flat -1):
- Confusing events (sets) with random variables, or confusing the relationship between and .
- Failing to specify the range of or handling ambiguously.
- Logical gap (flat -1):
- After obtaining , jumping directly to the conclusion without mentioning .