Question
In a regular square pyramid , the base is a square of side . The apex is directly above the center of the base, and . Find the dihedral angle along edge between planes and .
Step-by-step solution
Set up coordinates with the base in and center at the origin: Plane is , so a normal vector is . For plane , use two direction vectors in the plane: A normal vector is Let be the dihedral angle (the angle between the two planes). Then \cos\theta=\frac{|\vec n_1\cdot\vec n_2|}{|\vec n_1||\vec n_2|}=rac{1}{\sqrt5}.
Final answer
The dihedral angle satisfies (so ).
Marking scheme
1. Checkpoints (max 7 pts total)
- Coordinate setup (2 pts): Place the square base of side in with correct center and height .
- Normal vectors (3 pts): Find for the base plane and for plane .
- Angle computation (2 pts): Compute .
2. Zero-credit items
- Using a 2D triangle angle in a face as the dihedral angle without justification.
- Giving without any normal-vector work.
3. Deductions
- Cross-product mistake (-1): incorrect .
- Normalization/arithmetic error (-1): incorrect computation of .