If and , and exists (or is ±∞), then:
If and , and exists (or is ±∞), then:
Evaluate:
Solution: This is 0/0 form. Apply L'Hospital:
Evaluate:
Solution: Apply L'Hospital twice:
If is times differentiable on an interval containing and , then:
where the Lagrange remainder is:
for some between and .
Find: Maclaurin series of
Solution: Since for all :
Find: Maclaurin series of
Solution: The derivatives cycle: sin, cos, -sin, -cos, ...
:
:
:
:
Find:
Find:
The n-th degree Taylor polynomial of at is:
The 3rd degree Taylor polynomial of at 0 is:
If has derivatives on an interval containing , then:
where for some between and .
The Taylor series converges to if and only if .
The Taylor series for converges for all because as .
L'Hospital's rule applies to 0/0 and ∞/∞ indeterminate forms. Both f and g must be differentiable near the limit point, and the limit of f'/g' must exist (or be ±∞).
Taylor's theorem states that if f is n+1 times differentiable, then f(x) = P_n(x) + R_n(x), where P_n is the n-th degree Taylor polynomial and R_n is the remainder term.
A Maclaurin series is a special case of a Taylor series centered at x₀ = 0. Taylor series can be centered at any point x₀.
Compute f(x₀), f'(x₀), f''(x₀), ..., f^(n)(x₀), then use the formula: f(x) = Σ [f^(k)(x₀)/k!] (x - x₀)^k.
The Lagrange remainder is R_n(x) = [f^(n+1)(ξ)/(n+1)!] (x - x₀)^(n+1) for some ξ between x₀ and x. It provides an error bound for the Taylor approximation.