A partition of is a finite set of points:
The subintervals are with lengths .
For a partition and sample points , the Riemann sum is:
A function is Riemann integrable on if there exists a number such that:
We write .
If is continuous on , then is Riemann integrable on .
Evaluate:
Solution: Using FTC with :
If is continuous on , then the function:
is differentiable on and:
For :
By MVT for integrals, with:
As , , so:
If is an antiderivative of on , then:
Let . By FTC Part 1, .
Since and , we have .
Therefore for some constant .
Since , we have .
Thus , so . ∎
Evaluate:
Solution: Since :
If is continuous on , then there exists such that:
For on :
So , giving .
If and the derivative of is continuous on , then:
Evaluate:
Let , then :
Evaluate:
Let , :
For any :
If on , then:
The Riemann integral is defined as the limit of Riemann sums as the partition becomes finer. A function f is Riemann integrable on [a,b] if the limit exists and is independent of the choice of sample points.
FTC connects the two main operations of calculus: differentiation and integration are inverse operations. This lets us evaluate definite integrals using antiderivatives instead of limits of Riemann sums.
If F is an antiderivative of f on [a,b], then ∫ₐᵇ f(x)dx = F(b) - F(a). This is the fundamental connection between definite and indefinite integrals.
Key properties include: linearity (∫[f+g] = ∫f + ∫g), additivity (∫ₐᵇ + ∫ᵇᶜ = ∫ₐᶜ), reversal (∫ₐᵇ = -∫ᵇᵃ), and monotonicity (if f ≤ g, then ∫f ≤ ∫g).
Yes! Use ∫ₐˣ = -∫ˣₐ. For ∫_{g(x)}^{h(x)} f(t)dt, differentiate as: f(h(x))h'(x) - f(g(x))g'(x).