From the locus definition to exam-style line intersection techniques—learn the ellipse with diagrams, formulas, an interactive calculator, and a practice quiz.
Definition
Distance sum to foci is constant (2a)
Standard form
x²/a² + y²/b² = 1 (a>b>0) or x²/b² + y²/a² = 1
Parameter relation
c² = a² − b², e = c/a (0<e<1)
Area
A = πab
Latus rectum
Length = 2b²/a
Enter parameters and click Calculate to see results.
Locus definition
An ellipse is the set of points P such that the sum of distances to two fixed points (the foci) is constant:
Here a is the semi-major axis length. The foci are separated by distance 2c.
Standard equations
Horizontal major axis (foci on x-axis):
Vertical major axis (foci on y-axis):
Parameter relation
Once you know a and b, the focus parameter is fixed:
The parameters satisfy c² = a² − b², with foci at (±c, 0) (horizontal major axis).
The latus rectum has length 2b²/a. It is the shortest focal chord and appears often in exam problems.
Vertices & axis lengths
For a horizontal ellipse, the vertices are (±a, 0) and the co-vertices are (0, ±b).
Major axis length
2a
Minor axis length
2b
Eccentricity
Eccentricity measures how “stretched” the ellipse is:
Larger e means the foci are farther apart and the ellipse is flatter.
Eccentricity is e = c/a, with 0 < e < 1. When e increases, the foci move farther apart and the ellipse becomes less “round”.
Focal radius (horizontal ellipse)
Let P(x₀, y₀) lie on the ellipse, and foci be F₁(−c,0), F₂(c,0). The two focal radii satisfy:
Memory cue: “left plus, right minus” when foci are on the x-axis.
Latus rectum
The chord through a focus perpendicular to the major axis has constant length:
It is the shortest focal chord and is frequently used in parameter problems.
Common “shape reasoning”
Substitute the line into the ellipse to get a quadratic. Use the discriminant to determine whether it is a secant, tangent, or exterior line.
Horizontal major axis
Vertices: (±a,0)
Foci: (±c,0)
Vertical major axis
Vertices: (0,±a)
Foci: (0,±c)
Tip: Decide the orientation first (where the foci lie), then write down vertices and foci in one line.
Intersection workflow
Discriminant classification
Vieta inside geometry
Many invariants (fixed midpoint, fixed area, slope product constant) come from expressing everything using x₁+x₂ and x₁x₂. This avoids solving for the two intersection points explicitly.
Typical move
Convert chord length / triangle area / midpoint conditions into algebraic expressions of Vieta sums/products.
Focal chord ideas
A focal chord is any chord passing through a focus. Typical problems ask for:
Always start by writing the definition PF₁ + PF₂ = 2a and the relation e=c/a.
Fixed-point / fixed-value templates
Common exam templates often reduce to:
Strategy: express everything in terms of one parameter (slope k or intercept m), then eliminate it using the given condition to force an invariant.
Optical reflection property
An ellipse reflects rays from one focus to the other: if a light ray starts at F₁, reflects off the ellipse, it passes through F₂. This is why “whispering galleries” and certain reflective designs use ellipses.
Exam connection: problems may encode reflection as an angle condition which you translate into equal tangential angles at the point of reflection.
Kepler’s First Law (planetary orbits)
In classical mechanics, bound two-body orbits are ellipses with the central body at one focus. This is Kepler’s first law. While high-school analytic geometry doesn’t derive orbital mechanics, the same focal distance structure appears in many applications.
Useful intuition: e indicates “how non-circular” an orbit is—small e is near-circular, large e is elongated.
A compact summary (for speed)
One-liner
Ellipse: PF₁ + PF₂ = 2a.
Parameters
c² = a² − b², e = c/a.
Lengths
Area πab, latus rectum 2b²/a.
1) Forgetting orientation
Before writing foci and vertices, decide whether the major axis is horizontal or vertical. Many “wrong sign / swapped denominator” errors come from this.
2) Using the wrong relation for c
Ellipse: c² = a² − b². (Hyperbola uses c² = a² + b².)
3) Solving intersections too early
If a question asks for an invariant, don’t solve for both intersection points explicitly. Use Vieta (sum/product) first.