MathIsimple

Stochastic Processes – Problem 37: Prove that this Markov chain is positive recurrent

Question

Starting from the number 0, a fair coin is flipped each time. If the coin lands heads, the number increases by 1; if it lands tails, the number is divided by 2 and rounded down (floor). Prove that this Markov chain is positive recurrent.

Step-by-step solution

Step 1. The state space of this Markov chain is S={0,1,2,}S=\{0,1,2,\dots\}. The transition probabilities are pi,i+1=12p_{i,i+1}=\frac{1}{2} and pi,i/2=12p_{i,\lfloor i/2 \rfloor}=\frac{1}{2}. For any states i,jSi, j \in S, from 00 one can reach state jj in jj steps with probability (1/2)j(1/2)^j (via the path 01j0 \to 1 \to \dots \to j); from any state ii, repeated floor-halving reaches 00 in finitely many steps. Hence the chain is irreducible.

Step 2. Apply the Foster-Lyapunov criterion. Construct the Lyapunov function V(i)=iV(i) = i, so V(i)0V(i) \ge 0 and V(i)V(i) \to \infty as ii \to \infty. The one-step mean drift is ΔV(i)=E[V(Xn+1)V(Xn)Xn=i]=12(i+1)+12i/2i\Delta V(i) = E[V(X_{n+1}) - V(X_n) \mid X_n = i] = \frac{1}{2}(i+1) + \frac{1}{2}\lfloor i/2 \rfloor - i.

Step 3. When ii is even, say i=2ki = 2k: i/2=k=i/2\lfloor i/2 \rfloor = k = i/2, so ΔV(i)=12(i+1)+i4i=12i4\Delta V(i) = \frac{1}{2}(i+1) + \frac{i}{4} - i = \frac{1}{2} - \frac{i}{4}. When ii is odd, say i=2k+1i = 2k+1: i/2=k=(i1)/2\lfloor i/2 \rfloor = k = (i-1)/2, so ΔV(i)=12(i+1)+i14i=14i4\Delta V(i) = \frac{1}{2}(i+1) + \frac{i-1}{4} - i = \frac{1}{4} - \frac{i}{4}.

Step 4. Take the finite set F={0,1,2}F = \{0, 1, 2\}. For iFi \notin F (i.e., i3i \ge 3): if ii is even (i4i \ge 4), ΔV(i)=12i412\Delta V(i) = \frac{1}{2} - \frac{i}{4} \le -\frac{1}{2}; if ii is odd (i3i \ge 3), ΔV(i)=14i412\Delta V(i) = \frac{1}{4} - \frac{i}{4} \le -\frac{1}{2}. Hence for all iFi \notin F, ΔV(i)12\Delta V(i) \le -\frac{1}{2}.

Step 5. For states in FF, E[V(Xn+1)Xn=i]E[V(X_{n+1}) \mid X_n = i] is clearly finite. By Foster's theorem, since there exists a Lyapunov function VV, a finite set FF, and a constant ϵ=12>0\epsilon = \frac{1}{2} > 0 such that the mean drift is at most ϵ-\epsilon outside FF and finite inside FF, the irreducible chain is positive recurrent.

Final answer

QED.

Marking scheme

This rubric is based on the official solution (Foster-Lyapunov criterion).


1. Checkpoints (max 7 pts total)

Score exactly one chain | take the maximum subtotal among chains; do not add points across chains.

Chain A: Foster-Lyapunov Criterion / Pakes' Lemma (Recommended)

  • Irreducibility
  • State that the chain is irreducible (e.g., from 0 any state jj is reachable, and any state jj eventually returns to 0). [1 pt]
  • Lyapunov function choice
  • Construct V(i)=iV(i) = i (or V(i)=ciV(i)=ci, c>0c>0; or another valid function with V(i)V(i) \to \infty). [1 pt]
  • Mean drift computation (Heavy Lifting)
  • Write the correct expression for ΔV(i)\Delta V(i) combining both transition probabilities. [1 pt]
  • Correctly simplify to obtain the expression with a negative dominant term (e.g., 12i4\frac{1}{2} - \frac{i}{4}). [1 pt]
  • Drift bound analysis
  • Argue that for sufficiently large ii (or outside a finite set FF), the drift is at most ϵ-\epsilon for some ϵ>0\epsilon > 0. [2 pts]
  • *If only qualitatively stating "drift tends to -\infty" without specifying the finite set FF and uniform bound, award 1 pt.*
  • Criterion conclusion
  • Cite Foster-Lyapunov criterion (or Foster's theorem / Pakes' lemma) to conclude positive recurrence. [1 pt]

Chain B: Direct Definition / Stationary Distribution Existence

  • Irreducibility: State irreducibility. [1 pt]
  • Balance equations: Correctly write the balance equations for π\pi. [1 pt]
  • Series convergence proof (Heavy Lifting): Rigorously prove πj<\sum \pi_j < \infty. [4 pts]
  • Conclusion: State existence of a normalizable stationary distribution implies positive recurrence. [1 pt]

Total (max 7)


2. Zero-credit items

  • Only copying transition rules without derivation.
  • Only listing definitions of Markov chain or positive recurrence without connecting to the problem.
  • Incorrectly claiming "since transition probabilities sum to 1, the chain is positive recurrent."
  • Only computing specific paths without a general proof.
  • Claiming the chain is null recurrent or transient.

3. Deductions

  • Logical contradiction: Computing ΔV(i)0\Delta V(i) \ge 0 but concluding positive recurrence. (-2 pts)
  • Missing condition: Completely ignoring the finite set FF in Foster's theorem. (-1 pt)
  • Conceptual error: Confusing recurrence with positive recurrence. (-1 pt)
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