Question
Let be a martingale with , where is a constant. Prove that the sequence of random variables converges in the mean-square sense.
Step-by-step solution
Step 1. Given that is a martingale with . By Doob's martingale convergence theorem, there exists a random variable such that almost surely and in . However, here we need to verify mean-square convergence ( convergence), which requires showing that an -bounded martingale also converges in .
Step 2. For an -bounded martingale, is a uniformly bounded set in and is a martingale in : (since by the martingale property , and taking square-integrability into account the covariance is as above). More directly: for , Since , by conditional Jensen's inequality (or orthogonality): Therefore is nondecreasing in and bounded above by , hence converges to some finite limit .
Step 3. For , since converges. Therefore is a Cauchy sequence in .
Step 4. Since is complete, there exists such that Moreover, this coincides with the almost sure limit (since mean-square convergence implies convergence in probability, and the almost sure limit is unique). Therefore converges in mean square to .
Final answer
QED.
Marking scheme
This rubric is based on the official solution and is designed to assess the student's mastery of the proof of convergence (mean-square convergence) of martingales.
1. Checkpoints (Total: 7 pts)
Score exactly one chain (Chain A or Chain B). If a student mixes methods, grade the most complete chain.
Chain A: Based on Cauchy Sequence [Official Solution Path]
- Key identity and orthogonality (3 pts): Derive or use the martingale property to prove the orthogonality relation: for , prove OR directly derive . (Note: If using the orthogonal increment method and noting for , thereby obtaining , this item receives full marks.) [additive]
- Monotonicity and convergence of the norm (2 pts): State that is a nondecreasing sequence in (or that is a submartingale), combined with the upper bound from the hypothesis, conclude that the sequence converges. [additive]
- Cauchy sequence determination (1 pt): Combine the conclusions from the previous two steps to state that , thereby asserting that is a Cauchy sequence in . [additive]
- Completeness and conclusion (1 pt): Invoke the completeness of (or Hilbert space property) to conclude that the Cauchy sequence must converge to some random variable . (Note: If the student only writes "since it is a Cauchy sequence it converges," this implicitly uses completeness and should receive credit.) [additive]
Chain B: Based on Maximal Inequality and Dominated Convergence (Doob's Maximal Inequality & DCT)
- Almost sure convergence (1 pt): Cite Doob's Martingale Convergence Theorem to state that almost surely. [additive]
- Maximal inequality and integrable domination (3 pts): Use Doob's maximal inequality to prove (i.e., ). [additive]
- Application of the Dominated Convergence Theorem (3 pts): Use the above integrable dominating function and apply the Dominated Convergence Theorem to prove . [additive]
2. Zero-credit items
- Only copying the problem conditions: e.g., only writing that is a martingale or , with no subsequent derivation.
- Circular reasoning: Assuming mean-square convergence and then deriving properties from it.
- Incorrect logic: Asserting convergence solely from "boundedness" (e.g., bounded convergence), ignoring that this does not hold in infinite-dimensional spaces (Cauchy property or monotonicity is needed).
- Only citing the theorem name: For a proof problem, if only writing "by Doob's convergence theorem the conclusion holds" with no derivation, this is treated as an incomplete proof (unless the exam explicitly allows direct citation of this theorem; otherwise typically receives 0 or very low marks).
3. Deductions
- Logic gap (Max -2): In Chain A, if the specific expression relating to is not established, and convergence of the norm is directly asserted to imply sequence convergence (confusing convergence of real sequences with convergence of random variable sequences).
- Notational confusion (Max -1): Confusing as a random variable with a constant, or failing to specify whether the limit symbol is in the sense or the real number sense, causing logical ambiguity.
- Limit object undefined (No penalty): If the Cauchy sequence property is proved but the convergence target "" is not explicitly written, as long as completeness is implicitly used, no deduction.